Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
We are asked in the problem to determine the value of x in the equation <span>4x² + 2x = 7 using completing the square method. in this case,
</span><span>4x² + 2x = 7
x2 + 0.5 = 1.75
(x + 0.25)^2 - 0.0625 = 1.75
</span>(x + 0.25)^2 = 1.8125
<span>x+0.25=1.3462
</span>x1 =1.0963
x2 =-1.5962
Answer:
Unknown answer so ye that mean I'm not sure about it
Step-by-step explanation:
Unknown answer so ye that mean I'm not sure about it
