The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]
Answer: - 84/3
Step-by-step explanation: hope this helps!
Hello from MrBillDoesMath!
Answer:
x = 31
Discussion:
angle A + angle C + angle B = 180 (180 degrees in a triangle)
angle A + 57 + 61 = 180 => (substitution)
angle A + 118 = 180 =>
angle A = 180 -118 = 62
By the congruence statement, angle A = angle D = 2x so
62 = 2x =>
x = 31
Thank you,
MrB
The answer is 20 because you would do (5-9) which is -4 multiplied by -5 is positive 20
