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3 years ago

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The length of a rectangle is 2 in. more than twice its width. if the perimeter of the rectangle is 28 in., find the dimensions o

f the rectangle.

1 answer:

Harlamova29_29 [7]3 years ago

8 0

Length = 2+w
Width = w

Perimeter = 2length + 2width
28 = 2(2+w) + 2(w)
28= 4+ 2w + 2w
24= 4w
6 =w

width =6
length = 8

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Step-by-step explanation:

Given

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<em>To solve this question; we'll simplify options a to do, one after the other</em>

a: $(\frac{6^9}{6^8})^2$

From laws of indices;

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This implies that;

$(\frac{6^9}{6^8})^2 = (6^{9-8})^2$

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