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Anit [1.1K]
3 years ago
6

Scott and Lana ride bikes a total of 64 miles in a week. Lana rides 8 fewer miles than Scott.How many miles does Lana ride each

week?
Mathematics
1 answer:
natka813 [3]3 years ago
3 0

lemme think ill brb

Step-by-step explanation:

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The scale on a drawing is 1 cm = 4.5 meters. If the length of the drawing is 6.2 cm, what is the actual length in meters?
Nataly [62]

Answer:

I think the awnser is 27.9

Step-by-step explanation:

4.5*6.2=27.9

7 0
3 years ago
A house purchased for $230,000 has lost 6% of its value each year for the last four years. What is the house worth now?
lutik1710 [3]
You can use the compound growth to work this out,

Firstly you need to make a multiplier for -6%;
1-(6/100) = 0.94

The you times the amount of money by 0.94 to the power of 4 because you are working out 4 years:
230000*0.94^4 = 179527.26

The answer is $179527.26,
Hope this helps! :)
3 0
3 years ago
Please help with this
snow_lady [41]

Answer:

B. -  \frac{9}{8}

Step-by-step explanation:

\huge\frac{ - 2 {a}^{ - 3} {b}^{2}  }{a}  \\  \\ \huge  =  \frac{ - 2  {b}^{2}  }{a \times{a}^{ 3} }   \\  \\ \huge =  \frac{ - 2  {b}^{2}  }{{a}^{ 4} }   \\  \\  \huge =  \frac{ - 2 \times  {3}^{2} }{ {( - 2)}^{4} }  \\  \\   \huge=  \frac{ - 2 \times 9}{16}  \\  \\  \huge  \red{=  -  \frac{9}{8} }

8 0
3 years ago
Evaluate the series 4-2+1-0.5+0.25 to s10. Round to the nearest tenth.
andrew11 [14]
6god is watching from views
7 0
3 years ago
Read 2 more answers
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
2 years ago
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