There are 7 brothers and 6 sisters. If all siblings sat in a row and the girls requested to be seated next to one another, how m
1 answer:
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Answer:
Step-by-step explanation:
6 x 20 = 120
10 - 6 = 4 and (8+6) - 20 = 6
(4 x 6) / 2 = 12
120 + 12 = 132
Given:
Solution:
To solve the equation, it would be best if we remove the root. We remove the root by squaring the equation, but first we need to move the root and the content to the left side.
Then square both side to remove the root
After removing the root, move all terms to the left side
sec² x - 2 sec x + 1 = 0
Do factorization, remember that
a² - 2a + 1 = (a - 1)²
So,
sec² x - 2 sec x + 1 = 0
(sec x - 1)² = 0
sec x - 1 = 0
sec x = 1
= 1
cos x = 1
cos x = cos 0°
x = 0°
Solution:
To solve the equation, it would be best if we remove the root. We remove the root by squaring the equation, but first we need to move the root and the content to the left side.
Then square both side to remove the root
After removing the root, move all terms to the left side
sec² x - 2 sec x + 1 = 0
Do factorization, remember that
a² - 2a + 1 = (a - 1)²
So,
sec² x - 2 sec x + 1 = 0
(sec x - 1)² = 0
sec x - 1 = 0
sec x = 1
cos x = 1
cos x = cos 0°
x = 0°