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3 years ago

Please check if right or give an answer ASAP

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

8 0

Answer:

I think its B

Step-by-step explanation:

Hope this helps.

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Christiana and Marlena opened their first savings accounts on the same day. Christiana opened her account with $55 and plans to

PolarNik [594]

Answer: it will take 4 months for the amount to be the same and the amount would be $95

Step-by-step explanation:

Let x represent the number if months it will take for the two accounts have the same amount of money.

Christiana opened her account with $55 and plans to deposit $10 every month. This means that the amount that in the account after x months would be

10x + 55

Marlena opened her account with $35 and plans to deposit $15 every month. This means that the amount that in the account after x months would be

15x + 35

For the amount in the accounts to be the same, the number of months would be

15x + 35 = 10x + 55

15x - 10x = 55 - 35

5x = 20

x = 20/5

x = 4

The amount would be

15 × 4 + 35

= 60 + 35

= $95

8 0

3 years ago

Read 2 more answers

HELP!!! Simplify cos^2 0 -1/ 4sin^2 0?

Shkiper50 [21]

We need to simpify the given expression. The given expression to us is ,

Given Expression :-

$\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta }$

Using Identity :-

$\sf\implies \red{ sin^2\theta + cos^2\theta = 1}$

So that :-

$\sf\implies - sin^2\theta = cos^2\theta -1$

We have :-

$\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta } \\\\\sf\implies\dfrac{ - sin^2\theta}{4sin^2\theta}=\boxed{\sf -\dfrac{1}{4}}$

Hence the required answer is -1/4. 

5 0

3 years ago

Janet set off on a bicycle trip at 7:30 a.m.

UNO [17]

the answer is 10:20.

Hint for the future: be sure to write in the full problem. I only knew the answer because I had to do it myself, but people need more context if they are going to help you.

3 0

3 years ago

What is the x-intercept? 2x-6y= 18

Wittaler [7]

The x-intercept is (9,0). Hope it help!

6 0

3 years ago

Solve the inequality! (3x - 2)^2 - 4x(2x-3) greater or equal 0

seraphim [82]

Solve:

(3x-2)^2-4x(2x-3)>=0

(3x-2)(3x-2)-8x^2+12x>=0

9x^2-12x+4-8x^2+12x>=0

The solution: x^2+4>=0

I hope I helped you with your solution! If you could give me brainliest, I would be very thankful!

3 0

3 years ago