Answer:
No. pp you can fit in a van: 6,
No. pp you can fit in a bus: 20
Step-by-step explanation:
Let v = # of pp in vans, and let b = # of pp in buses:
8v + 9b = 228,
4v + 5b = 124
If we solve this system of equations by substitution, we isolate the first eq. for v and then substitute into the bottom eq:
v = 228-9b/8,
Substitute v = 228-9b/8 into bottom eq:
[4 * 228-9b/8 + 5b = 125]
[228+b/2=124]
[228+b = 248]
[b = 20]
Now substitute 20 to find no. of pp in the vans:
v = 228 - 9(20)/8 = 228 - 180/8 = 48/8 = 6
Answer: In my opinion you could just shorten the number of orders so that it's not so long.
Explanation: The numbers can be from every 20 orders so 900, 920, 940...so on.
A graphing calculator is a great help for problems of this nature.
x ∈ {-5.63, -0.55, 2.59}
A=p(1+r)^t
A=650×(1+0.08)^(14)
A=1,909.18
Interest earned=a-p=1909.18-650=1,259.18
