<h2>
Answer:</h2>
0.006598wb
<h2>
Explanation:</h2>
The magnetic flux,Ф, (measured in weber, wb) through a given loop of wire is related to the area (A) of the wire and the magnetic field (B) in which the loop is placed as follows;
Ф = BA cos θ -----------------------(i)
<em>Where;</em>
θ = angle between the planar area of the coil and the magnetic flux
A = π d² / 4 [d = diameter of the loop]
<em>From the question;</em>
B = 0.84T
θ = 0° [since the plane of the loop is perpendicular to the field lines, it makes it parallel to the magnetic flux]
d = 10cm = 0.1m
=> A = π (0.1)² / 4 [Take π = 3.142]
=> A = 3.142 x (0.1)² / 4
=> A = 0.007855m²
<em>Substitute these values into equation (i) as follows;</em>
Ф = 0.84 x 0.007855 x cos 0°
Ф = 0.84 x 0.007855 x 1
Ф = 0.006598
Therefore, the magnetic flux through the loop is 0.006598wb