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nordsb [41]
3 years ago
7

Alkaline earth metals have a low density true false

Physics
1 answer:
Marta_Voda [28]3 years ago
6 0

true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

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You have developed a method in which a paint shaker is used to measure the coefficient of static friction between various object
Paladinen [302]

Answer:

0.62

Explanation:

A = Amplitude

f = Frequency = 1.85 Hz

\mu = Coefficient of static

g = Acceleration due to gravity = 9.81 m/s²

Angular frequency

\omega=2\pi f\\\Rightarrow \omega=2\pi\times 1.85

Maximum acceleration

a_{max}=A\omega^2\\\Rightarrow a_{max}=0.045\times (2\pi\times 1.85)^2

a_{max}=\mu g\\\Rightarrow \mu=\frac{a_{max}}{g}\\\Rightarrow \mu=\frac{0.045\times (2\pi\times 1.85)^2}{9.81}\\\Rightarrow \mu=0.62

Coefficient of static friction between penny and tabletop is 0.62

6 0
4 years ago
Which of the follwing is not a step toward planning your goals
LUCKY_DIMON [66]

Answer:

what are the steps that they give u?

5 0
2 years ago
A bicycle rider traveling east at 10 km/hr sees a blue car pass her appearing to travel west at 50 km/hr. What is the blue car's
BigorU [14]

Answer:

v_{bR} = 25 km/h towards west

Explanation:

As we know that the speed of the blue car as appear to the bicycle rider is given as

v_{bc} = 50 km/h towards west

also it is given that bicycle is moving at speed of 10 km/h towards East

so here we have

v_{bc} = v_b - v_c

so we have

v_b = v_{bc} + v_c

v_b = -50 + 10 = 40 km/h towards west

now speed of the red car is given as 15 km/h towards west

so here the relative speed of blue car with respect to red car is given as

v_{bR} = v_b - v_R

v_{bR} = 40 - 15 = 25 km/h towards west

8 0
4 years ago
An Atwood machine is constructed using a
Nesterboy [21]

Answer:

a=1.03 m/s²

Explanation:

given                                  required

dist=22.1 cm                    a=?

m1=2.1 kg

m2=1.56 kg

m3=1.93 kg

g=9.8 m/s²

solution

there are three forces on this system so we can solve by using newton's second law as follows

t1,t2,and weight of are the only forces acted on the system,

if we take the system on the left mass m3

-m3a=t2-m3g

-1.93 kg×a=t2-1.93 kg×9.8 m/s²

-1.93 kg×a=t2-18.91 N................................ eq 1

take at the right mass m2

m2a=t2-m2×g

1.56 kg×a=t2-1.56 kg×9.8 m/s²

1.56 kg×a=t2-15.288 N...................................2

add the two equations simultaneously and then solve for a,

-1×(-1.93 kg×a=t2-18.91 N) multiply by -1 the first and add the two equations

1.56 kg×a=t2-15.288 N

3.49 kg×a=3.622 N

a=1.03 m/s²

3 0
4 years ago
Solids in which the atoms have no particular order or pattern are called
posledela

Answer:

Amorphous solids are composed of atoms or molecules that are in no particular order. Each particle is in a particular spot, but the particles are in no organized pattern. Examples include rubber and wax. Crystalline solids have a very orderly, three-dimensional arrangement of atoms or molecules

Explanation:

8 0
3 years ago
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