Answer:
W = 8.92 10² kJ
Explanation:
For this exercise they give us the strength, we must calculate the distance traveled, for this we need the rocket acceleration let's use Newton's second law
F = m a
a = F / m
a = 20 103/1400
a = 14.29 m/s²
With kinematics we can find the distance traveled
² = v₀² + 2 a x
x = ( ²-v₀²) / 2 a
x = (50² -35²) / 2 14.29
x = 1275 / 28.58
x = 44.61 m
Let's calculate the work
W = F.d
The bold is vector; as indicated by the force is in the direction of movement the scalar product is reduced to the ordinary product
W = F d
W = 20 10³ 44.61
W = 8.92 10⁵ J
W = 8.92 10² kJ
Answer:
5.76N
Explanation:
We are given that
Distance between two charges ,
Electrostatic force=
Where k=
Substitute the values then we get
Hence, the electric force between two charges=5.76N
Answer:
f1 = -3.50 m
Explanation:
For a nearsighted person an object at infinity must be made to appear to be at his far point which is 3.50 m away. The image of an object at infinity must be formed on the same side of the lens as the object.
∴ v = -3.5 m
Using mirror formula,
i/f1 = 1/v + 1/u
Where f1 = focal length of the contact lens, v = image distance = -3.5 m, u = object distance = at infinity(∞) = 1/0
∴ 1/f1 = (1/-3.5) + 1/infinity
Note that, 1/infinity = 1/(1/0) = 0/1 =0.
∴ 1/f1 = 1/(-3.5) + 0
1/f1 = 1/(-3.5)
Solving the equation by finding the inverse of both side of the equation.
∴ f1 = -3.50 m
Therefore a converging lens of focal length f1 = -3.50 m
would be needed by the person to see an object at infinity clearly
A. Radioactive decay does not result in heat. Gravity also does not result in heat. In the Earth's mantle, it is highly unlikely that the radiation from the sun would reach that deep into the earth.
Answer:
minimum distance will be 13.33 m
Explanation:
We have given the speed of both the car = 80 km/h
We know that 1 km =1000 m
And 1 hour = 60×60 =3600 sec
So
Reaction time is given as t = 0.60 sec
Minimum distance will be equal to the distance driver needed during reaction time
So minimum distance = u ×t =22.22 ×0.60=13.33 m