This is the equation for the formation of magnesium chloride. Mg(s) + 2HCl(l) → MgCl2(aq) + H2(g) Which are the reactants and th
1 answer:
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Answer:
When blueshift happens, the perceived frequency of the wave would be higher than the actual frequency.
Explanation:
As the name suggests, when blueshift happens to electromagnetic waves, the frequency of the observed wave would shift towards the blue (high-frequency) end of the visible spectrum. Hence, there would be an increase to the apparent frequency of the wave.
Blueshifts happens when the source of the wave and the observer are moving closer towards one another.
Assume that the wave is of frequency at the source. In other words, the source of the wave sends out a peak after every
.
Assume that the distance between the observer and the source of the wave is fixed. It would then take a fixed amount of time for each peak from the source to reach the observer.
The source of this wave sends out a peak after each period of . It would appear to the observer that consecutive peaks arrive every
. That would correspond to a frequency of
.
On the other hand, for a blueshift to be observed, the source of the wave needs to move towards the observer. Assume that the two are moving towards one another at a constant speed of .
Again, the source of this wave would send out a peak after each period of . However, by the time the source sends out the second peak, the source would have been
closer to the observer then when the source sent out the first peak.
When compared to the first peak, the second peak would need to travel a slightly shorter distance before it reach the observer. Hence, from the perspective of the observer, the time difference between the first and the second peak would be shorter than . The observed frequency of this wave would be larger than the original
.
Complete Question
When you ascend or descend a great deal when driving in a car yours ears "pop," which means that the pressure behind the eardrum is being equalized to that outside. If this did not happen, what would be the approximate force on an eardrum of area .50 cm2 if a change in altitude of 950 m takes place?
Answer:
The value is
Explanation:
From the question we are told that
The area of the ear drum is
The change in altitude is
Generally the change in pressure is mathematically represented as
This can also be mathematically represented as
So
=>
=>
Here is the density of dry air with value
So
=>