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alexandr1967 [171]
3 years ago
12

P-(x, 2)y =(2,-2)P Q = 5 units​

Mathematics
1 answer:
kow [346]3 years ago
3 0

Answer

[P - (x,2)], [Y]

=(2, -2), [PQ]

=5 units

and y=0

Step-by-step explanation:

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Evgesh-ka [11]
Anwser:

22.5 or 5/22 or 30

Step-by-step Explanation:

-2 and -2
SSS
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but that’s not a fraction so you do

22.5 or 5/22

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3 years ago
The radius of a circle is 13 centimeters. What is the circle's circumference? Use 3.14 for ​.
vlabodo [156]

Answer:

The circumference is 81.64cm

Step-by-step explanation:

Circumference of a circle=2×3.14×radius

2×3.14×13=81.64

I hope this helps you in any way :)

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3 years ago
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enyata [817]

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Step-by-step explanation:

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2 years ago
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xz_007 [3.2K]

Answer:  There are 50 students in the drama club and 34 students in the yearbook club

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3 0
3 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

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3 years ago
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