Answer:
<em>Answers below</em>
Step-by-step explanation:
<u>Equation</u>
Let's call:
p = number of pennies Janesa has in her pocket
n = number of nickels Janesa has in her pocket
She has 24 coins in total, thus:
![p + n=24\qquad\qquad [1]](https://tex.z-dn.net/?f=p%20%2B%20n%3D24%5Cqquad%5Cqquad%20%5B1%5D)
Since each penny is worth $0.01 and each nickel is worth $0.05, and Janesa has $1 in total:

Multiplying by 100:
![p+5n=100\qquad\qquad [2]](https://tex.z-dn.net/?f=p%2B5n%3D100%5Cqquad%5Cqquad%20%5B2%5D)
A. Completing the equation:

B.
From [1]:

Substituting into [2]:

Simplifying:

Rearranging:



B. There are 5 pennies in Janesa's pocket
C. Since each penny is worth $0.01, the total value of pennies is 5*$0.01=$0.05
The total value of the pennies is $0.05
D. The total value of the nickels is 19*$0.05 = $0.95
E. Jackson should say she has 19 nickels and 5 pennies
4+6^2+9•3-10
PEMDAS
P=parentheses
E=exponent
m=multiplication
d=division
a=addition
s=subtraction
*no parentheses in this equation
*exponent = 6^2
6^2=36
4+36+9•3-10
*multiplication = 9•3
9•3=27
4+36+27-10
*addition=4+36+27
4+36+27=67
67-10
*subtraction=67-10
67=10=57
ANSWER=57
please give brainliest itd mean a lot<3
Answer:
height = 20.5068 m
Step-by-step explanation:
Given the data in the question;
First, lets calculate the amplitude, midline and period of 8minutes
Amplitude = 35 / 2 = 17.5
|A| = 17.5
A = - 17.5 { since the wheel starts at 6 o clock }
midline C = (35/2) + 3
C = 17.5 + 3
C = 20.5
And period is 8 minutes
⇒ 2π/B = 8
8B = 2π
B = 2π/8 = π/4
So our equation will be in the form of;
y = h(t) = Acos(B×t) + C
∴ h(t) = -17.5cos( π/4×t) + 20.5
Now, How high are you off the ground after 6 minutes
⇒ height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( 4.71238898) + 20.5
height = -17.5 × cos( 4.712) + 20.5
height = -17.5 × -0.00038898 + 20.5
height = 0.0068 + 20.5
height = 20.5068 m
Answer:
The speed of the cars is 
Step-by-step explanation:
First we must first have the clear concept that
or 
Our question is the speed of the cars then the variable to clear will be s.
Let's raise the equation for each car taking into account that we have the following data:
Car 1:
,
and 
Car 1:
,
and 
The two cars travel the same distance so we will raise the distance formula for each car and then match them.
<em>Car 1</em>



<em>Car 2</em>







The speed of the cars is 32 km/hr
The answer is 9/42. might be wrong I'm rusty on this.