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mafiozo [28]
3 years ago
6

Suppose a package delivery company purchased 14 trucks at the same time. Five trucks were purchased from manufacturer A, four fr

om manufacturer B, and five from manufacturer C. The cost of maintaining each truck was recorded. The company used ANOVA to test if the mean maintenance costs of the trucks from each manufacturer were equal. To apply the F test, how many degrees of freedom must be in the denominator?
Mathematics
1 answer:
nikklg [1K]3 years ago
5 0

Answer:

14

Step-by-step explanation:

Given that a package delivery company purchased 14 trucks at the same time. Five trucks were purchased from manufacturer A, four from manufacturer B, and five from manufacturer C. The cost of maintaining each truck was recorded.

No of companies  = 3

No of items in total = 14

Total df = 17-1=16

degrees of freedom between groups = 3-1 =2

Hence degrees of freedom for denominator

=16-2 =14

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Okay, let's see...

The problem is asking for a linear equation most likely in the form of y=mx+b

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Let's start with the y intercept first.

Y intercept means ' When does the line touch (intercept) the y axis.

In this case, if you look at the graph, the line <em>touches </em>the y axis at -1.

-1 will replaces b

To find the slope we are going to take 2 precise points from the graph.

Lets use <em>(0,-1)</em> and <em>(-6,4) </em>

To find the slope, we're going to use \frac{(y_{2}  -y_{1} )}{(x_{2} -x_{1} )}

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f(x)=\frac{-5}{6} x -1

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Poin
egoroff_w [7]

Answer: \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

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Let the required point be P.

AP:AB=3:4

AP:PB=AP:(AB-AP)=3:(4-1)=3:1

It means, point P divides segment AB in 3:1.

Section formula:  If a point divides a line segment in m:n, then

\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Using section formula, we get

P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)

P=\left(\dfrac{-9-5}{4},\dfrac{9-4}{4}\right)

P=\left(\dfrac{-14}{4},\dfrac{5}{4}\right)

P=\left(\dfrac{-7}{2},\dfrac{5}{4}\right)

Therefore, the required point is \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

6 0
3 years ago
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ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

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6 0
3 years ago
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