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ANTONII [103]
3 years ago
6

Two mechanics work on a car . The first mechanic worked 10 hours and the second mechanic worked for 15 hours. Together they char

ged a total of $2050. What was the rate charged by each mechanic if the sum of the two rates was $16 per hour? Please help
Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

Answer:

110

Step-by-step explanation:

Let x = rate #1 and then 155-x=rate #2.

15x + 5(155-x) = 1225

15x - 5x + 775 - 1225

10x = 450

x = 45, second rate is 110

katrin2010 [14]3 years ago
8 0
The answer is 110 I hope this helps
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Mr. Hughes gave 5/14
kow [346]

Answer:

His savings were of $4,200.

Step-by-step explanation:

Mr. Hughes gave 5/14 of his savings to his son, 2/3 of the remainder to his daughter, and the rest to his wife:

This means that the son and daughter amount is:

\frac{5}{14} + \frac{2}{3}(\frac{9}{14})

As \frac{9}{14} is the remained that his son did not get. So

\frac{5}{14} + \frac{2}{3}(\frac{9}{14}) = \frac{15}{42} + \frac{18}{42} = \frac{33}{42}

Fraction his wife got:

1 - \frac{33}{42} = \frac{42}{42} - \frac{33}{42} = \frac{9}{42}

If his wife got $900, what were his savings?

Total savings are x, wife got \frac{9}{42} of x. So

\frac{9x}{42} = 900

9x = 900*42

x = \frac{900*42}{9}

x = 100*42

x = 4200

His savings were of $4,200.

5 0
3 years ago
74.88 x 8 rounded to the nearest cent
mafiozo [28]

Answer:

74.88*8=599.04

Correct answer is 599

Step-by-step explanation:

This would be the answer with cents.

But you have to round to the nearest whole number which would be 599

Hope this helps mark brainliest please :)

8 0
2 years ago
What is 0.5, three sixteenths, 0.75, and five and forty eighths in order from least to greatest
butalik [34]
I'm just estimating here, 
5/48,3/16,0.5,0.75
8 0
4 years ago
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
Whats 69x420?????????
IRISSAK [1]

Answer:

28980

Step-by-step explanation:

Also "<em>nice</em>"

3 0
3 years ago
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