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Nataly_w [17]
3 years ago
6

USING the Midpoint Formula , POINT A is at (-3,-5) and point M is at (-0.5,0). what are the coordinates of point B

Mathematics
1 answer:
Rasek [7]3 years ago
7 0

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x-3}{2}~~,~~\cfrac{y-5}{2} \right)~~=~~\stackrel{\stackrel{Midpoint}{M}}{(-0.5~,~0)}\implies \begin{cases} \cfrac{x-3}{2}=-0.5\\[1em] x-3=-1\\ \boxed{x= 2}\\ \cline{1-1} \cfrac{y-5}{2}=0\\[1em] y-5=0\\ \boxed{y=5} \end{cases}

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The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Feliz [49]

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Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 50

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

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Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{50}

Z = 0.4

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0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0
4 years ago
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