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Oksi-84 [34.3K]
3 years ago
12

Find the sum of the measures of the interior angles in the figure.

Mathematics
1 answer:
Schach [20]3 years ago
8 0

Answer:

128.57 degrees per angle

Step-by-step explanation:

There is a total of 900 degrees in a seven sided polygon. Divide the number by seven and you get your answer.

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Mike recently increased the size of his Jeep tires from the original 29 inch diameter to the larger 33.73 inch diameter. If Mike
coldgirl [10]

Answer:

I believe it is C

Step-by-step explanation:

Please correct me if i am wrong ^w^

3 0
3 years ago
Read 2 more answers
Please help solve the for x. <br> I'm offering 20 points
andrew11 [14]

Answer:

1/-21

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

17

4

x+

−1

12

=6x

Step 2: Subtract 6x from both sides.

17

4

x+

−1

12

−6x=6x−6x

−7

4

x+

−1

12

=0

Step 3: Add 1/12 to both sides.

−7

4

x+

−1

12

+

1

12

=0+

1

12

−7

4

x=

1

12

Step 4: Multiply both sides by 4/(-7).

(

4

−7

)*(

−7

4

x)=(

4

−7

)*(

1

12

)

x=

−1

21

3 0
3 years ago
En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0
3 years ago
How do you work out 7 2/5 -5 3/5 by subtracting mixed numbers with borrowing
Marat540 [252]

Answer:

1 4/5

Step-by-step explanation:

37/5-5 3/5

37/5-28/5

9/5

1 4/5

6 0
3 years ago
Can you help show me where they belong ? pls help asap
kozerog [31]

y=3x, y=(2/7)x,-0.5=y are all on direct the other ones are on the other side i just did the question they correct. :)

5 0
3 years ago
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