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love history [14]
3 years ago
12

How many times will22 go into 988?

Mathematics
2 answers:
geniusboy [140]3 years ago
7 0
It will go in 44 times
Sever21 [200]3 years ago
6 0
22 will go into 988 a total of 44.9090909 times
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Determine whether the geometric series 27 + 18 + 12 + 8 + ... converges or diverges, and identify the sum if it exists.
Ne4ueva [31]

The given geometric series as shown in the question is seen to; Be converging with its' sum as 81

<h3>How to identify a converging or diverging series?</h3>

We are given the geometric series;

27 + 18 + 12 + 8 + ...

Now, we see that;

First term; a₀ = 27

Second Term; a₁ = 2(27/3)

Third term; a₂ = 2²(27/3²)

Fourth term; a₃ = 2³(27/3³)

Thus, the formula is;

2ⁿ(27/3ⁿ)

Applying limits at infinity gives;

2^(∞) * (27/3^(∞)) = 0

Since the  terms of the series tend to zero, we can affirm that the series converges.

The sum of an infinite converging series is:

S_n = a/(1 - r)

S_n = 27/(1 - (2/3)

S_n = 81

Read more about converging or diverging series at; brainly.com/question/15415793

#SPJ1

6 0
2 years ago
[<br> 1<br> What is the distance between the points (-4, -8) and (10,-8)?<br> Need help
Vedmedyk [2.9K]

Answer:

2

Step-by-step explanation:

√(-8-8)^2 +(10+4)^2=

✓-32+28

✓4

=2

3 0
3 years ago
What is the variance for 34, 46, 52, 29, 41, 38, 36, and 28
horsena [70]

Answer:

38

Step-by-step explanation:

add all the numbers and divide that number by the amount of numbers there.

34+46+52+29+41+38+36+28 / 8 = 304/8 = 38

8 0
3 years ago
Read 2 more answers
Three fair coins are tossed. If all land "heads," the player wins $10, and if exactly two land heads, the player wins $5. If it
hodyreva [135]

Answer:

<u>After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:</u>

<u>1/8 or 12.5% of landing three "heads"</u>

<u>3/8 or 37.5% of landing two "heads"</u>

<u>4/8 or 50% of landing no or only one "head".</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

If three coins land "heads" the player wins $ 10

If two coins land "heads" the player wins $ 5

Cost of playing = $ 4

2.  What is the player's expected outcome after four games?

Probability of two coins out of three lands "heads" = 3/8

Probability of three coins out of three lands "heads" = 1/8

Now, let's calculate the player's expected outcome, as follows:

Four games:

Cost = 4 * 4 = $ 16

Worst-case scenario: No wins

Best-case scenario: 4 out of 4 of $ 10 win

Worst-case scenario profit or loss = 0 - 16 = Loss of $ 16

Best-case scenario profit or loss = 40 - 16 = Profit of $ 24

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

8 0
3 years ago
Find the inverse for the linear function g(x)=1/4-3
Dimas [21]
G (x) = -11/4 ...

that's your answer
7 0
3 years ago
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