The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
<h3>What are permutation and combination?</h3>
A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.
It is given that:
On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:
The required number of ways:
= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))
= 2[2[ 1 + 5 + 15+35] + 70]
= 364
Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
Learn more about permutation and combination here:
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a > b
A . a^5b^3/ab^4 = a^4/b
B. a^4 / a*a*a*a = a^4 / a^4 = 1
C. ab^2 / a^2b = b/a
D. b*b*b/b^3 = b^3/b^3 = 1
B and D, doesn't matter what values of a and b it's always equal 1
Lets say a = 2 and b = 1
A. a^4/b = 2^4 / 1 = 16/1 = 16
C. b/a = 1/2 = 0.5
So C has the least value
Answer:
ab^2 / a^2b
Rise = 4
Run = 5
Slope = 4/5
Step-by-step explanation:
(a) n² + 3
First term = 1² + 3 = 4
Second term = 2² + 3 = 7
Third term = 3² + 3 = 12
Fourth term = 4² + 3 = 19
10th term = 10² + 3 = 103
(b) 2n²
First term = 2(1)² = 2
Second term = 2(2)² = 8
Third term = 2(3)² = 18
Fourth term = 2(4)²= 32
10th term = 2(10)² = 200
Hence, this is the required solution.
