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3 years ago

_____ Contains hydrolytic enzymes associated with the intracellular digestion of macromolecules

Chemistry

1 answer:

stealth61 [152]3 years ago

8 0

Answer:

Lysosome contains hydrolytic enzymes associated with the intracellular digestion of macromolecules.

Explanation:

Lysosome is found in all types of eukaryotic cells, and it is responsible for the digestion of old cell parts, micro-organism and macromolecules. Lysosome is surrounded by a membrane which maintains the interior acidic environment with the help of proton pump.

Lysosome contains unique membrane proteins and wide variety of hydrolytic enzymes such as acid hydrolyses that are helping in the breakdown of macromolecules (proteins, nucleic acid and polysaccharides). Lysosome acid dependent activity helping to protect the cell from self degradation in the situation of lysosomal rupture or leakage, while the pH of the cell is neutral to slightly alkaline.

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AleksandrR [38]

Answer:

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Explanation:

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3 years ago

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3 years ago

Consider the equilibrium

vladimir1956 [14]

Answer:

$Kp^{1000K}=0.141\\Kp^{298.15K}=2.01x10^{-18}$

$\Delta _rG=1.01x10^5J/mol$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$C_2H_6(g)\rightleftharpoons H_2(g)+C_2H_4(g)$

Thus, Kp for this reaction is computed based on the given molar fractions and the total pressure at equilibrium, as shown below:

$p_{C_2H_6}^{EQ}=2bar*0.592=1.184bar\\p_{C_2H_4}^{EQ}=2bar*0.204=0.408bar\\p_{H_2}^{EQ}=2bar*0.204=0.408bar$

$Kp=\frac{p_{C_2H_4}^{EQ}p_{H_2}^{EQ}}{p_{C_2H_6}^{EQ}}=\frac{(0.408)(0.408)}{1.184}=0.141$

Now, by using the Van't Hoff equation one computes the equilibrium constant at 298.15K assuming the enthalpy of reaction remains constant:

$Ln(Kp^{298.15K})=Ln(Kp^{1000K})-\frac{\Delta _rH}{R}*(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=Ln(0.141)-\frac{137000J/mol}{8.314J/mol*K} *(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=-40.749\\\\Kp^{298.15K}=exp(-40.749)=2.01x10^{-18}$

Finally, the Gibbs free energy for the reaction at 298.15K is:

$\Delta _rG=-RTln(Kp^{298.15K})=8.314J/mol*K*298.15K*ln(2.01x10^{-18})\\\Delta _rG=1.01x10^5J/mol$

Best regards.

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4 years ago

Why do scientists use the scientific method?

xeze [42]

Answer:

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Explanation:

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