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ikadub [295]
3 years ago
11

Which is the BEST evidence that a chemical change has occurred?

Chemistry
1 answer:
MaRussiya [10]3 years ago
3 0

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According to the rate law (rate = k[a]m[b]n), what does the rate of a reaction depend on?
Andreyy89
Concentration of the reactant,pressure,surface
 area of the reactant  and temperatur
8 0
3 years ago
• Draw lewis dot structures for an atom of each of following elements:
marin [14]

Answer:

Explanation:

Lewis dot structures represent the symbol of an atom we're looking at and the number of valence electrons it has. This number is represented by the sum of dots around the symbol.

  • Potassium is in group 1A, this means it only has one valence electron, so we draw K with one dot in its Lewis diagram;
  • Argon is in group 8A, this means it has eight valence electrons, so we draw Ar with 8 dots around it in its Lewis diagram;
  • Silicon is in group 4A, this means it has four valence electrons, so we draw Si with 4 dots around it in its Lewis diagram;
  • Arsenic is in group 5A, this means it has five valence electrons, so we draw As with 5 dots around it in its Lewis diagram.

Those are represented in the image attached below:

5 0
2 years ago
If a tank of gas contains 4 L of N O2 how many molecules are in it
Jobisdone [24]

but heres a way to solve it

An athlete takes a deep breath, inhaling 1.85 L of air at 21°C and 754 mm Hg.

T

How many moles of air are in the breath? How many molecules?

Gas constant, R= 8.314 J mol ¹ K-1

PV = nRT

PV

RT

h=

=

P

= 0.08206 L atm mol-1 K-1

= 62.36 L Torr mol-1 K-1 -

1 atm = 760 mm Hg = 760 Torr

754 Forr 1.85€

6236 Jerr 294K

3 0
2 years ago
A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this
erastova [34]

Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the <em>PV=nRT </em>formula, where:

  • P = 2.4 atm
  • V = 250 mL ⇒ 250 / 1000 = 0.250 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 15 °C ⇒ 15 + 273 = 288 K

We <u>input the given data</u>:

  • 2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K

And <u>solve for n</u>:

  • n = 0.025 mol

Finally we <u>calculate how many particulates are there in 0.025 moles</u>, using <em>Avogadro's number</em>:

  • 0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates
6 0
2 years ago
an object is placed at 0 on a number line.it moves 3 units to the right,then 4units to the left,and then 6 units to the right th
Evgen [1.6K]
It should probably be on a positive 5
4 0
3 years ago
Read 2 more answers
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