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Anvisha [2.4K]
3 years ago
12

23. What is the molarity of NO3- in each solution?

Chemistry
1 answer:
Sauron [17]3 years ago
6 0

Answer:

Explanation:

A) 0.150

B) 0.300

C) 0.450

hope it helps:)

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Write the balanced chemical equation for the following reaction. Phases are optional. Solid calcium chlorate decomposes to form
Tanya [424]

Answer:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Explanation:

1)<u> Word equation (given)</u>

  • <em>calcium chlorate (solid) → solid calcium chloride (solid)  + oxygen (gas)</em>

2) <u>Chemical formulae of the reactant and products</u>:

  • <em><u>Calcium chlorate</u></em><em>: </em>

The most common oxidation states of chlorine are -1, +1, +3, +5, +7.

The suffix ate in chlorate means that chlorine atom is with the third lowest oxidation state (counting only the positive states). So, this is +5.

The oxidation state of calcium is +2.

Hence, the chemical formula of calcium chlorate is Ca(ClO₃)₂

  • <u><em>Calcium chloride</em></u>

The suffix ide in chloride means that chlorine is with oxidation state -1. Again the oxidation state of calcium is +2.

Hence, the chemical formula of calcium chloride is CaCl₂

  • <u><em>Oxygen</em></u>

Oxygen gas is a diatomic molecule, so its chemical formula is O₂.

  • <u><em>Phases</em></u>

The symbols s and g (in parenthesis) indicate the solid and gas phases respectively.

3) <u>Chemical equation</u>:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + O₂ (g)

That equation is not balanced becasue the number of O atoms in the reactant side and in the product side are different.

4)<u> Balanced chemical equation:</u>

Add a 3 as coefficient in front of O₂(g), in the product side to balance:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Verify that all the atoms are balanced:

Atom    Reactant side      Product side

Ca             1                           1

Cl              2                          2

O              3×2 = 6                2×3 = 6

Conclusion: the equation is balanced and the final answer is:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)
5 0
4 years ago
Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.
algol13

Answer : The value of \Delta G_{rxn} is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.1)^3}{(1.4)^2}

Q=3.375

Now we have to calculate the value of \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -28.0 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)

\Delta G_{rxn}=-24.9kJ/mol

Therefore, the value of \Delta G_{rxn} is -24.9 kJ/mol

5 0
3 years ago
You have used 2.4×102 L of distilled water for a dialysis patient. How many gallons of water is that?
Alinara [238K]

Answer:

63.36gallons

Explanation:

Given:

Volume of water used for dialysis = 2.4 x 10²L

Solution:

We are to convert from liters to gallons.

The conversion factor is shown below:

                1L = 0.264gallons

To convert to litre:

       since 1L = 0.264gallons

             2.4 x 10²L = (2.4 x 10² x 0.264)gallons; 63.36gallons

3 0
4 years ago
Describe and explain how petrol is separated from the mixture of hydrocarbons in crude oil.
lara31 [8.8K]
The crude oil is heated in a process of fractional distillation (note: you can research this online if you require more detail) and this process causes different hydrocarbons to condense at different heights up the distillation column. They will therefore run down the side of the column and into different areas depending on their boiling point.
7 0
4 years ago
Which radioactive isotope would take the least amount of time to become stable? rubidium-91 iodine-131 cesium-135 uranium-238
Masteriza [31]
The answer is rubidium -91 because it takes a shorter time of 58.4 seconds to become stable.
5 0
3 years ago
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