All categories

3 years ago

23. What is the molarity of NO3- in each solution?

Chemistry

1 answer:

Sauron [17]3 years ago

6 0

Answer:

Explanation:

A) 0.150

B) 0.300

C) 0.450

hope it helps:)

You might be interested in

The equation that represents

dlinn [17]

CH and O is the reactants while CO and H2O is the products

6 0

3 years ago

Describe what happens when ice changes<br> into liquid water.

chubhunter [2.5K]

Answer:

When ice changes into liquid water it melts. The solidified ice in the frozen, would melt via the burning sun shooting its streaks down at the ice. Which causes the ice to melt, and turn into liquid water.

Explanation:

pp poopoo

3 0

3 years ago

Determine the heat energy needed to raise the temperature of 120 grams of ice at -5 to steam at 115°

CaHeK987 [17]

Answer:

Q = 30355.2 J

Explanation:

Given data:

Mass of ice = 120 g

Initial temperature = -5°C

Final temperature = 115°C

Energy required = ?

Solution:

Specific heat capacity of ice is = 2.108 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT = T2 -T1

ΔT = 115 - (-5°C)

ΔT = 120 °C

Q = 120 g × 2.108 j/g.°C × 120 °C

Q = 30355.2 J

5 0

3 years ago

Help!

maks197457 [2]

Answer:

First 1-5 in pics

I can't upload further reactions

Explanation:

sandmeyer's reaction
swarts reaction
Finkelstein reaction
wurtz reaction
reimer teimann reaction

6. Lucas test

ROH + Zncl2 +HCl ---> RCl + H2O

7. esterification

R-OH +R’-COOH +H+↔ R’-COOR

3 0

2 years ago

Pls help me with this

Zina [86]

Answer:

$[I_2]=[Br]=0.31M$

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

$I_2+Br_2\rightleftharpoons 2IBr$

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

$K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}$

Thus, we solve for x as show below:

$\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M$

Therefore, the concentrations of both bromine and iodine are:

$[I_2]=[Br]=2.0M-1.69M=0.31M$

Regards!

8 0

3 years ago