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3 years ago

What is the expression in radical form?

Mathematics

1 answer:

BabaBlast [244]3 years ago

3 0

Answer:

32x^9y^6/5

Step-by-step explanation:

Factor (4x^3y^2)^3 and get 2^6(x^3)^3(y^2)^3

Factor 10: 2 x 5

Then get 2^6(x^3)^3(y^2)^3/2 x 5

Cancel the common factor, 2

2^5(x^3)^3(y^2)^3/5

(x^3)^3=x^9

2^5x^9(y^2)^3/5

(y^2)^3=y^6

2^5x^9y^6/5

2^5=32

32x^9y^6/5

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Answer:

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3 years ago

(60 points)

natka813 [3]

Answer:

Step-by-step explanation:

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$5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}$

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