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3 years ago

Solve x squared minus 2x minus 15 equals 0 using the zero product property

1 answer:

4 0

X^2 - 2x - 15 = 0

(x - 5)(x + 3) = 0

We have two factors:

(x - 5) and (x + 3)

Set each factor to 0 and solve for x.

Take it ftom here.

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Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final c

Black_prince [1.1K]

Answer:

The test statistic value Z = 4.64 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

Test the claim that the proportion of all children in the town who suffer not from asthma is 11%

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 167

Given data In a sample of 167 children selected randomly from one town, it is found that 37 of them suffer from asthma.

Sample proportion

$p^{-} = \frac{x}{n} = \frac{37}{167} = 0.2215$

Given Population proportion 'P' = 11% = 0.11

Step(ii) :-

Null Hypothesis : H₀ : p = 11

Alternative Hypothesis H₁: p≠11

Test statistic

$Z = \frac{p^{-} -P }{\sqrt{\frac{P Q}{n} } }$

$Z = \frac{0.2215 -0.11 }{\sqrt{\frac{0.11 X 0.89}{167} } }$

Z = 4.64

step(iii)

Critical value Z = 1.96

The calculated value Z = 4.64 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

Conclusion:-

Test the claim that the proportion of all children in the town who suffer not from asthma is 11%

4 0

3 years ago

The function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237. Find the a

trapecia [35]

Answer:

29 is answer.

Step-by-step explanation:

Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.

To find average velocity of the object over the interval of time [1,3]

We know that derivative of s is velocity and antiderivative of velocity is position vector .

Since moving along a line equation of s is

use two point formula

$\frac{s-150}{237-150} =\frac{t-2}{5-2} \\s=29t-58+150\\s=29t+92$ gives the position at time t.

Average velocity in interval (1,3)

= $\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29$

5 0

3 years ago

Solve for p in the literal equation 3p + 41 =q.

denis23 [38]

Answer:

The answer is 44 because 3+41=44

7 0

2 years ago

Evaluate a-b for a=5 and b=(-8)

Rudik [331]

Answer:

Step-by-step explanation:

a = 5

b = -8

5 - -8 = 13

3 0

2 years ago

Read 2 more answers

the perimeter of a rectangle is 70m. What are the dimensions that will produce the maximum area of such a rectangle

rusak2 [61]

Answer:

17.5, divide 70 by 4

Step-by-step explanation:

what i said above

3 0

3 years ago