Solve for r.

Hadley has 3/6 of a box of white envelopes and 1/3 of a box of gray envelopes. When full, each box of envelopes has the same num

QveST [7]

Answer:

<u>The two statements that apply are A and B.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

White envelopes Hadley has = 3/6 of a box

Gray envelopes Hadley has = 1/3 of a box

When full, each box of envelopes has the same number of envelopes

Hadley said she has 4/9 of a box when she puts the white envelopes and gray envelopes together.

2. Which statements describe this situation? Select the two statements that apply.

Let's add 3/6 and 1/3

3/6 + 1/3 = 3/6 + 2/6 = 5/6

A. Hadley’s answer is incorrect, because 3/6 is equal to 1/2 , and 4/9 is less then 1/2 . This is correct.

B. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 5/6. This is correct.

C. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 2/6. This is wrong

D. Hadley's answer is correct, because 3 and 1 is 4, and 6 and 3 is 9. This is wrong.

<u>The two statements that apply are A and B.</u>

3 0

3 years ago

A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If the silo is to have a volume of 505π ft3,

Romashka-Z-Leto [24]

Answer:

radius x = 3 ft

height h = 23,8 ft

Step-by-step explanation:

From problem statement

V(t) = V(cylinder) + V(hemisphere)

let x be radius of base of cylinder (at the same time radius of the hemisphere)

and h the height of the cylinder, then:

V(c) = π*x²*h area of cylinder = area of base + lateral area

A(c) = π*x² + 2*π*x*h

V(h) = (2/3)*π*x³ area of hemisphere A(h) = (2/3)*π*x²

A(t) = π*x² + 2*π*x*h + (2/3)*π*x²

Now A as fuction of x

total volume 505 = π*x²*h + (2/3)*π*x³

h = [505 - (2/3)* π*x³ ] /2* π*x

Now we have the expression for A as function of x

A(x) = 3π*x² + 2π*x*h A(x) = 3π*x² + 505 - (2/3)π*x³

Taking derivatives both sides

A´(x) = 6πx - 2πx² A´(x) = 0 6x - 2x² = 0

x₁ = 0 we dismiss

6 - 2x = 0

x = 3 and h = [505 - (2/3)* π*x³]/2* π*x

h = (505 - 18.84) / 6.28*3

h = 23,8 ft

7 0

3 years ago

What is the surface area of the Triangular Prism rounded to the nearest tenth?

Illusion [34]

Answer:

C. 43.6

Step-by-step explanation:

you need to take the area of each shape

lets do the skinny triangles first on the top and bottom of this shape.

so to find the formula of triangle we need to do 0.5 * 1.26 * 5.3

because the formula of a triangle is half the base times height.

so we get 0.5 * 1.26 * 5.3 = 3.339

multiply it by two and we get 6.678

now lets find the area of the huge rectangle on the back/behind of the shape

3.3*5.3 = 17.49

now lets find the area of the two smaller rectangles

3.3 * 3.6 = 11.88

2.3 * 3.3 = 7.59

now lets add

6.678 + 17.49 + 11.88 + 7.59 = 43.638

round it to 43.6

8 0

2 years ago

Read 2 more answers

I have been on this question for so long if anyone can help me I would greatly appreciate it. Thank you

Phoenix [80]

Answer:

Step-by-step explanation:

let x be the number

2(x+8)=-4x+4

2x+16=-4x+4

6x=-12

x=-2

8 0

3 years ago

Read 2 more answers

1a. [1 mark] The price per kilogram of tomatoes, in euros, sold in various markets in a city is found to be normally distributed

andrey2020 [161]

Answer:

The price that is two standard deviations above the mean price is 4.90.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 3.22 and a standard deviation of 0.84.

This means that $\mu = 3.22, \sigma = 0.84$