How to write a chemistry formula

2. Write the balanced equation for the following:

Ostrovityanka [42]

Answer:

2CH3CHOHCH3 + 9O2 ----> 6CO2 + 8H2O

Explanation:

It will be a clean burn ( no smoke).

3 0

3 years ago

If a small amount of br2 is added to an aqueous solution of an unknown monosaccharide, the reddish-brown color of br2 will disap

Natalija [7]

Answer:
<span>If a small amount of br2 is added to an aqueous solution of an unknown monosaccharide, the reddish-brown color of br2 will disappear if the monosaccharide is <u>an Aldose</u>.

Explanation:
This happens because the Aldose contains a carbonyl group called Alsedyde. Bromine being a oxidizing agent oxidizes the aldehyde functional group to Carboxylic Acid moiety. While this test is not positive in case of Ketonic Functional group.</span>

4 0

3 years ago

58-Ni has an atomic number of 28 which are the protons and a mass number of 58. Since the mass number is 58 this is the protons

Kaylis [27]

Answer:

Explanation: Nickel is element number 28 on the period table with a mass number 58 or 60, it exist in two forms and the phenomenon is known as isotopy

Definition of Isotopy is simply a phenomenon whereby elements exist in various forms that have the exact same chemical properties but different atomic mass.

58-Ni has atomic number 28 because that's the number o the element on the periodic table. Proton number is the same as atomic number and same as electron number for a neutral element or element without charge.

Mass number = Proton number (P) + Neutron number (N)

58 = 28 + N

N= 58-28

N= 30

58-Ni has 28 has the atomic number, proton number and electron number because it is a neutral atom but the neutron is 30 as shown in the calculation above.

60-NI+2 has a contrasting figure because the element has a charge of +2

Mass number= Proton + Neutron

60 = 28 + N

N= 60 - 28

N= 32

Electron = Proton - Charge

28 - (+2)

28 - 2

Electron = 26

The number of electron in 60-Ni +2 differs from 58-Ni because of the number of charge

Electron number differs from proton number in any element with a charge.

5 0

4 years ago

Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30 at 25°C. Identify the solution as acidic, basic or

Norma-Jean [14]

Answer:

Option A) 2.6 × 10⁻¹¹ M, acidic.

Explanation:

The ion-product constant of water $K_{\rm w}$ gives a relationship between $\rm [H_3O^{+}]$ and $\rm [OH^{-}]$ :

$K_{\rm w} = \rm [H_3O^{+}]\cdot [OH^{-}]$ .

The exact value of $K_{\rm w}$ depends on the temperature. Under $\rm 25^{\circ}C$ , $K_{\rm w} \approx 1^{-14}$ .

The question states that $\rm [H_3O^{+}] = 3.9\times 10^{-4}\; M$ . As a result,

$\begin{aligned} {\rm [OH^{-}]} &= \frac{K_{\rm w}}{[{\rm H_3O^{+}}]}\\ &\approx\frac{1^{-14}}{3.9\times 10^{-4}} && \rm {\leftarrow Only~under~25^{\circ}C.}\atop{}\\&\approx \rm 2.6\times 10^{-11}\; M\end{aligned}$ .

A solution is acidic if $\rm [H_3O^{+}] > [OH^{-}]$ .
A solution is neutral if $\rm [H_3O^{+}] = [OH^{-}]$ .
A solution is acidic if $\rm [H_3O^{+}] < [OH^{-}]$ .

$\rm [H_3O^{+}] > [OH^{-}]$ for this solution. As a result, this solution is acidic.

8 0

3 years ago

I need to know what is oxidized and what is reduced.

pishuonlain [190]

Answer:

1. Reduction: O₂ ; Oxidation: S

2. Reduction: F ; Oxidation: Al

3. Reduction: Zn ; Oxidation: H

Explanation:

Determine the oxidation state of each element:

2 CoS → Cobalt acts with +2, S with -2

O₂ is at ground state. In ground state the elements has oxidation state of 0.

In CoO, the oxygen acts with -2

The oxidation state has decreased; oxygen was reduced.

In SO₂, sulfur acts with +4; oxidation state has increased, so S has been oxidized.

2. Both reactants are at ground state.

In AlF₃ Al has oxidation state of +3 and F, -1

Al increased the oxidation state → oxidation

F decreased the oxidation state → reduction

3. Hydrogen has 0 as oxidation state. In water, H has +1

It was increased → oxidation

Zn acts with +2, in the zinc oxide. As we have elemental Zn, the oxidation state is 0; it has decreased → reduction

4 0

3 years ago