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yan [13]
3 years ago
13

the volume of a gas with a pressure of 1.2 atmospheres increases from 1 to 4 what is the final pressure of the gas assuming cons

tant temperature ​
Chemistry
1 answer:
Oksana_A [137]3 years ago
7 0

Answer:

the answer is is putting ptessure on the gas

Explanation:

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Indicar la cantidad de sustancia en: a) 2.0L de un gas en C.N; b) 22.4 mL de un gas a 755 torr y 26 grados celsius?
nekit [7.7K]

Answer:

El termopar B presenta un mayor grado de dispersión y también es más preciso. ... (c) La estimación para T = 175 ° C es probablemente la más cercana al valor real, porque el ... (cm3). Flujo de masa. Velocidad. (kg / min). Diferencia. Duplicar. (Di). Yo y yo. 2. 1 ... atm de gas. 2. 2. 2 f. 3. 2 f f. 30 14,7 lb 20 pulg. 4 14,7 lb 24 pulg 392 lb 7,00 10 lb pulg.

8 0
2 years ago
ASAP, NO TROLLS 20 points!!!!
MA_775_DIABLO [31]

Answer:

1.- Chemical change

2.- Because the atoms in the image are tranformed into a new molecule

3.- Yes, it does

4.- Due to the amount of atoms are the same both in products and reagents

Explanation:

6 0
2 years ago
Read 2 more answers
Calculate ΔG o for the following reaction at 25°C: 3Mg(s) + 2Al3+(aq) ⇌ 3Mg2+(aq) + 2Al(s) Enter your answer in scientific notat
larisa [96]

Answer:

-3.7771 × 10² kJ/mol

Explanation:

Let's consider the following equation.

3 Mg(s) + 2 Al³⁺(aq) ⇌ 3 Mg²⁺(aq) + 2 Al(s)

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

ΔG° = 3 mol × (-456.35 kJ/mol) + 2 mol × 0 kJ/mol - 3 mol × 0 kJ/mol - 2 mol × (-495.67 kJ/mol)

ΔG° = -377.71 kJ = -3.7771 × 10² kJ

This is the standard Gibbs free energy per mole of reaction.

5 0
3 years ago
Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b
Lelechka [254]

Answer:

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

Explanation:

A typical carbon–carbon bond requires 348 kJ/mol=348000 J/mol

Energy required to breakl sigle C-C bond:E

E=\frac{348000 J/mol}{6.022\times 10^{23} mol^{-1}}=5.7788\times 10^{-19} J

E=\frac{h\times c}{\lambda}

where,

E = energy of photon

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of the radiation

Now put all the given values in the above formula, we get the energy of the photons.

\lambda =\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{5.7788\times 10^{-19} J}

\lambda =3.4398\\times 10^{-7}m=343.98 nm

1 m = 10^{9} nm

343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.

4 0
3 years ago
A(n)____is the smallest particle of an element that has the chemical properties of that element.
AnnyKZ [126]

Answer:

Atom

Explanation:

8 0
3 years ago
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