The mass, in grams, of hydrogen that would be produced from the reaction will be 0.102 grams
<h3>Stoichiometric calculations</h3>
From the balanced equation of the reaction:
The mole ration of magnesium to water is 1:2.
Mole of 4.73 grams Mg = 4.73/24.3 = 0.195 moles
Mole of 1.83 grams water = 1.83/18 = 0.102 moles
Hence, water is limiting.
Mole ratio of water to the hydrogen produced = 2:1
Equivalent mole of hydrogen gas produced = 0.102/2 = 0.05 moles
Mass of 0.05 moles hydrogen gas = 0.05 x 2 = 0.102 grams
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Answer:
Explanation:
stoichiometry of C₂H₂ to H₂O is 2:2.
Number of moles of C₂H₂ = molar mass of C₂H₂
Since the molar mass of C₂H₂ is 26 g/mol.
Number of C₂H₂ moles reacted = 64.0 g / 26 g/mol = 2.46 mol.
according to a molar ratio of 2:2.
the number of H₂O moles formed = a number of C₂H₂ moles reacted.
Therefore the number of H₂O moles produced = 2.46 mol
Answer:
2-methylene propylbenzene
Explanation:
The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.
The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;
i) alkylation
ii) addition
The product of the major organic product of the reaction is 2-methylene propylbenzene.
Answer:
CH4+ 2Cl2→CH2Cl2+ 2HCl
Explanation:
mass is 132.8`125
as methane and dichlormethane has the same molar ration 1 to 1
mol of ch4 is 1.5625
so 1.5625 times mr of ch2cl2 is 132.8125
Answer:
Explanation:
Phosphoric acid H₃PO₄ is produced from reaction of water and tetraphosphorus decoxide P₄O₁₀ as follows
P₄O₁₀ + 6 H₂O = 4 H₃PO₄
In this reaction 6 molecules of H₂O and one molecule of phosphorus compound P₄O₁₀ is needed to produce phosphoric acid , ie the conversion factor of water to acid is 6 / 1
This ratio is called mole ratio of water to H₃PO₄.
So the required ratio is 6 : 1 .
