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3 years ago

Please help answer Noah’s incorrect claim

Mathematics

1 answer:

PolarNik [594]3 years ago

5 0

Answer:

a subset of integers

Step-by-step explanation:

You have to look at the definition of the variable and the meaning of the function value in order to determine suitable domain values.

Here, the variable is defined as a number of dimes. It must be a non-negative integer, a subset of the integers. (We cannot count fractional dimes or negative dimes.)

___

Since the variable represents "a handful of dimes", there must be an upper limit on its value. We expect that it will be something less than 1000 (20 rolls of dimes), but it might be slightly more.

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Find the 22th term in the arithmetic sequence<br> 23,14,5,-4

Darya [45]

Answer:

-45

Step-by-step explanation: no explanation

3 0

3 years ago

A cylinder has a height of 12 inches and a radius of 1.5 inches. What is its voulme? Round your answer to the nearest tenth. Use

USPshnik [31]

Find the area of the top, which is a circle.

Area of a circle = pi x r^2

Area = 3.14 x 1.5^2 = 7.065

Now for the volume multiply the area of the top by the height:

7.065 x 12 = 84.78 cubic inches

Round to the nearest tenth: 84.8 cubic inches

8 0

3 years ago

Read 2 more answers

What is the product of 2x + y and 5x – y + 3? x2 + xy + x + y2 + y

miskamm [114]

Answer: $10x^2+3xy+6x-y^2+3y$

Step-by-step explanation:

You need to remember the Product of powers property:

$(a^m)(a^n)=a^{(m+n)}$

Then, knowing this property, now you have to apply the Distributive property. So:

$(2x+y)(5x-y+3)=\\\\=(2x)(5x)-(2x)(y)+(2x)(3)+(y)(5x)-(y)(y)+(y)(3)\\\\=10x^2-2xy+6x+5xy-y^2+3y$

Finally, to simplify this expression, you need to add the like terms.

Therefore, you get that the product is:

$=10x^2+3xy+6x-y^2+3y$

3 0

3 years ago

Read 2 more answers

Use limits to find the area of the region bounded by the graph f(x)=4-2x^3 , the x-axis , and the vertical lines x=0 and x=1

gtnhenbr [62]

Answer:

$\frac{7}{2}$ square units.

Step-by-step explanation:

We have to use limits to find the area of the region bounded by the graph $f(x) = 4 - 2x^{3}$ , the x-axis, and the vertical lines x=0 and x=1.

So, the area will be

A = $\int\limits^1_0 {(4 - 2x^{3})} \, dx$

= $[4x - \frac{x^{4}}{2} ]^{1} _{0}$

= $4 - \frac{1}{2}$

= $\frac{7}{2}$ square units. (Answer)

3 0

3 years ago

Find the area of the figure.

konstantin123 [22]

Answer:

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Explanation:

All you need to do is separately find the area of the shapes that are part of the figure (in this case the trapezoid and rectangle), and then add them all up.

1.(7x4) + (1/2x8[7+19])

2. 28 + 104

3. 132

~Hope this helps you~

4 0

3 years ago