The first evidence that gravity outside our solar system worked the same way as it does inside is that Herschel measured the two stars that make up the Castor system moved around each other
<h3>What is a Solar system ?</h3>
The Sun, eight planets, their moons, comets, asteroids, meteoroids, and dwarf planets make up a solar system, which revolves around the Sun. Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune are the eight planets that revolve in a particular order around the Sun.
- Although there are more than 3,200 other stars in our galaxy with planets around them, our solar system is the only one that is formally referred to as a "solar system."
- The closest stellar system to our solar system, Alpha Centauri, is one of the brightest stars in the southern skies and is only 4.3 light-years away.
Learn more about Solar system here:
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Answer:
1 x 10¹⁸cm
Explanation:
Given parameters:
Velocity of light = 300,000,000cm/s
Unknown:
Distance in centimeters = ?
Solution:
To solve this problem,
The velocity of light is 3 x 10⁸m/s
Velocity =
Distance = velocity x time = 3 x 10⁸m/s x 3.2 x 10⁷s
= 9.6 x 10¹⁵m
To cm;
100cm = 1m
Distance = 9.6 x 10¹⁵ x 10² = 9.6 x 10¹⁷cm = 1 x 10¹⁸cm
N<u><em>umber 3</em></u>
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Sand. sand is much lighter and can be carried further
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1