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2 years ago

5

A rod of length 0.82 m, rotating with an angular speed, 4.2 rad/s, about axes that pass perpendicularly through one end, has a m

ass of 0.63 kg, which is distributed uniformly along its length. Find the kinetic energies of the rod.

1 answer:

mariarad [96]2 years ago

5 0

Answer:

Explanation:

KE = ½Iω²

ΚΕ = ½(mL²/3)ω²

ΚΕ = ½(0.63(0.82²)/3)4.2²

ΚΕ = 1.24541928

KE = 1.2 J

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