ANSWER: y= 3x - 6
STEP-BY-STEP EXPLANATION:
(1,-3) and (3,3)
X1=1 X2=3
Y1= - 3 Y2=3
1) Find the slope of the line.
To find the slope of the line passing through these two points we need to use the slope formula:
m = 
m= 
m=
= 3
2)Use the slope to find the y-intercept.
Now that we know the slope of the line is 3 we can plug the slope into the equation and we get:
y= 3x+b
Next choose one of the two point to plug in for the values of x and y. It does not matter which one of the two points you choose because you should get the same answer in either case. I generally just choose the first point listed so I don’t have to worry about which one I should choose.
y= 3x+b point (1,-3)
-3= 3(1) + b
-3-3=b
-6=b
3)Write the answer.
Using the slope of 3 and the y-intercept of -6 the answer is:
y = 3x - 6
Answer:
y = -4
Step-by-step explanation:
First, let's find the slope. Since the line is horizontal, it's slope has to be 0 (this is because slope = rise/run, there is no "rise" in a horizontal line therefore the slope is 0)
Now, we need to find the y-intercept. This is where the line intercepts the y-axis. Looking at the graph, the line intercepts the axis at (0,-4), therefore the y-intercept is -4.
The equation would be:
y=0x-4
y=-4
a = prt
a = 24,000 x 0.06 x(48 / 12)(you have to turn months into years)
a = 24,000 x 0.06 x 4
a = $5,760
The payment due is $5,760
Answer:
1 and -5
Step-by-step explanation:
![~~~~~x^3+3x^2-9x+5=0\\\\\implies x^3-x^2+4x^2-4x-5x+5=0\\\\\implies x^2(x-1)+4x(x-1)-5(x-1)=0\\\\\implies (x-1)(x^2 +4x -5) = 0\\\\\implies (x-1)(x^2+5x -x -5) = 0\\\\\implies (x-1)[x(x+5) -(x+5)] =0\\\\\implies (x-1)(x-1)(x+5)= 0\\\\\implies (x-1)^2(x+5) = 0\\\\\implies x = 1,~~ x = -5](https://tex.z-dn.net/?f=~~~~~x%5E3%2B3x%5E2-9x%2B5%3D0%5C%5C%5C%5C%5Cimplies%20x%5E3-x%5E2%2B4x%5E2-4x-5x%2B5%3D0%5C%5C%5C%5C%5Cimplies%20x%5E2%28x-1%29%2B4x%28x-1%29-5%28x-1%29%3D0%5C%5C%5C%5C%5Cimplies%20%28x-1%29%28x%5E2%20%2B4x%20-5%29%20%3D%200%5C%5C%5C%5C%5Cimplies%20%28x-1%29%28x%5E2%2B5x%20-x%20-5%29%20%3D%200%5C%5C%5C%5C%5Cimplies%20%28x-1%29%5Bx%28x%2B5%29%20-%28x%2B5%29%5D%20%3D0%5C%5C%5C%5C%5Cimplies%20%28x-1%29%28x-1%29%28x%2B5%29%3D%200%5C%5C%5C%5C%5Cimplies%20%28x-1%29%5E2%28x%2B5%29%20%3D%200%5C%5C%5C%5C%5Cimplies%20x%20%3D%201%2C~~%20x%20%3D%20-5)
Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.
