1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
astra-53 [7]
3 years ago
5

A number is doubled and then increased by nine. The result is ninety- Three. What is the original number?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

42

Step-by-step explanation:

First you subtract 93 by 9. You get 84. Then you divide it by 2. Which is your answer, 42.

This can be represented as:

93=2x+9

First subtract 9 from both sides

84=2x

Then divide by 2 on both sides

42=x

You might be interested in
How many solutions does the system of equations below have?
soldier1979 [14.2K]

Answer:

One solution                    

Step-by-step explanation:

5x + y = 8

15x + 15y = 14

Lets solve using substitution, first we need to turn "5x + = 8" into "y = mx + b" or slope - intercept form

So we solve for "y" in the equation "5x + y = 8"

5x + y = 8

Step 1: Subtract 5x from both sides.

5x + y − 5x = 8 − 5x

Step 2: 5x subtracted by 5x cancel out and "8 - 5x" are flipped

y = −5x + 8

Now we can solve using substitution:

We substitute "-5x + 8" into the equation "15x + 15y = 14" for y

So it would look like this:

15x + 15(-5x + 8) = 14

Now we just solve for x

15x + (15)(−5x) + (15)(8) = 14(Distribute)

15x − 75x + 120 = 14

(15x − 75x) + (120) = 14(Combine Like Terms)

−60x + 120 = 14

Step 2: Subtract 120 from both sides.

−60x + 120 − 120 = 14 − 120

−60x = −106

Divide both sides by -60

\dfrac{ -60x  }{ -60  }   =   \dfrac{ -106  }{ -60  }

Simplify

x =   \dfrac{ 53  }{ 30  }

Now that we know the value of x, we can solve for y in any of the equations, but let's use the equation "y = −5x + 8"

\mathrm{So\:it\:would\:look\:like\:this:\ y =  -5 \left(  \dfrac{ 53  }{ 30  }    \right)  +8}

\mathrm{Now\:lets\:solve\:for\:"y"\:then}

y =  -5 \left(  \dfrac{ 53  }{ 30  }    \right)  +8}

\mathrm{Express\: -5 \times   \dfrac{ 53  }{ 30  }\:as\:a\:single\:fraction}

y =   \dfrac{ -5 \times  53  }{ 30  }  +8

\mathrm{Multiply\:-5 \:and\:53\:to\:get\:-265 }

y =   \dfrac{ -265  }{ 30  }  +8

\mathrm{Simplify\:  \dfrac{ -265  }{ 30  }    \:,by\:dividing\:both\:-265\:and\:30\:by\:5} }

y =   \dfrac{ -265 \div  5  }{ 30 \div  5  }  +8

\mathrm{Simplify}

y =  - \dfrac{ 53  }{ 6  }  +8

\mathrm{Turn\:8\:into\:a\:fraction\:that\:has\:the\:same\:denominator\:as\: - \dfrac{ 53  }{ 6  }}

\mathrm{Multiples\:of\:1: \:1,2,3,4,5,6}

\mathrm{Multiples\:of\:6: \:6,12,18,24,30,36,42,48}

\mathrm{Convert\:8\:to\:fraction\:\dfrac{ 48  }{ 6  }}

y =  - \dfrac{ 53  }{ 6  }  + \dfrac{ 48  }{ 6  }

\mathrm{Since\: - \dfrac{ 53  }{ 6  }\:have\:the\:same\:denominator\:,\:add\:them\:by\:adding\:their\:numerators}

y =   \dfrac{ -53+48  }{ 6  }

\mathrm{Add\: -53 \: and\: 48\: to\: get\:  -5}

y =  - \dfrac{ 5  }{ 6  }

\mathrm{The\:solution\:is\:the\:ordered\:pair\:(\dfrac{ 53  }{ 30  }, - \dfrac{ 5  }{ 6  })}

So there is only one solution to the equation.

5 0
2 years ago
What are the solutions to the quadratic equation <img src="https://tex.z-dn.net/?f=x%5E2%20%2B40%3D0" id="TexFormula1" title="x^
Mandarinka [93]

Answer:

In disguise right arrow In Standard Form a, b and c

x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1

2(w2 − 2w) = 5 Expand (undo the brackets),

and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5

z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3

Step-by-step explanation:

sorry it took so long

7 0
3 years ago
Is the product 1.01 1.01 less than or greater than 1?
faust18 [17]

Answer:

greater than 1

Step-by-step explanation:

its greater because 1.01 is greater than 1

8 0
3 years ago
How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?
Anastasy [175]

Whenever you can invert a function, you have that the graphs of f(x) and its inverse f^{-1}(x) are reflected with respect to the line y=x

So, given any point on the graph of f^{-1}(x), you can simply swap its coordinates to get the correspondent point on the original function f(x)

As an example, all exponential functions pass through the point (0,1), while all the logarithmic functions pass through the point (1,0)

6 0
3 years ago
Read 2 more answers
Jacob opened a money-market account. In the first month, he made an initial deposit of $500, and
natima [27]

Answer:

after 13 months

Step-by-step explanation:

........ur welcome..........

1475-500=975

975÷75=13

so 13 months

6 0
3 years ago
Other questions:
  • The difference in the x-coordinates of two points is 3. and the difference in the y-coordinates of the two points is 6
    6·2 answers
  • Find the derivative of f(x) = 5 divided by x at x = -1. (1 point)
    13·1 answer
  • how can i create a linear inequality with both a constant and a linear term on each side and that ha x&gt;7 as a solution.
    5·1 answer
  • Elijah bought 3 3/4 pounds of groind hamburger meat for $11.00. What is the price per pound of the ground hamburger meat. Roind
    6·2 answers
  • What is the product of 1/2x-1/4 and 5x^2-2x+6
    5·1 answer
  • I need help with this question
    7·1 answer
  • Solve for x: x-10= -12
    10·1 answer
  • 3. Emma said that when you multiply three negative decimals , the product will be positive . Use these numbers to answer the que
    12·1 answer
  • Lines p and q are parallel. Which are the angle measures of
    11·1 answer
  • 2 of 5
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!