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kifflom [539]
3 years ago
15

The histogram below shows the number of weeks Jimmy spent different amounts of money to fill the gas tank in his car. If the gra

ph is redrawn so that the scale on the y-axis begins with zero, which aspect of the graph will change the most? The difference in the heights of the bars will not appear as great. The difference in the heights of the bars will be more pronounced. The graph will appear more skewed to the left. The graph will appear more skewed to the right.
Mathematics
2 answers:
sammy [17]3 years ago
6 0

Answer:

A. The difference in the heights of the bars will not appear as great.

Step-by-step explanation:


mrs_skeptik [129]3 years ago
3 0

Answer:

The difference in the heights of the bars will not appear as great.

Step-by-step explanation:

Since we are asked what the difference would be if the scale on the y-axis beings with 0, this tells us that the current graph does <em>not</em> start at 0.

Comparing two histograms of the same data, one that starts at 0 and one that does not start at 0, we will see that the heights of the bars on the graph that does not start at 0 seem to be much more different.

This is because when we compare, for example, a height from 20 to 50, where the next goes from 20 to 30 (20 difference compared to the actual height of the highest bar being 30), the differences in heights are much more pronounced than they would be if the bars went from 0 to 50 and from 0 to 30 (20 difference compared to the highest of 50).

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At a concert 20% of the people are wearing black dress suits,1/4 are wearing navy,0.35 are wearing brown,and the rest are wearin
yan [13]

Answer:67

Step-by-step explanation: cause tghe number is not a number

5 0
3 years ago
...........................
cupoosta [38]

Answer:

3/5 or 0.6

Step-by-step explanation:

Here, given the value of tan theta , we want to find the value of sine theta

Mathematically;

tan theta = 0pposite/adjacent

Sine theta = opposite/hypotenuse

Firstly we need the length of the hypotenuse

This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.

Let’s call the hypotenuse h

h^2 = 3^2 + 4^2

h^2 = 9 + 16

h^2 = 25

h = √(25)

h = 5

Now from the tan theta, we know that the opposite is 3

Thus, the value of the sine theta = 3/5 or simply 0.6

5 0
4 years ago
This is a continuous set of points in the coordinate plane. It can be, but is not always, straight.
castortr0y [4]

Answer:

Linear. While all linear equations produce straight lines when graphed, not all linear equations produce linear functions. In order to be a linear function, a graph must be both linear (a straight line) and a function (matching each x-value to only one y-value).

5 0
3 years ago
It is given that D is inversely proportional to v m
Darina [25.2K]

Answer:

Step-by-step explanation:

D=\frac{k}{\sqrt{m}}\\\\64=\frac{k}{\sqrt{9}}\\\\64=\frac{k}{3}\\\\ 64*3=k\\\\k=192\\a)D=\frac{192}{\sqrt{4}}\\\\=\frac{192}{2}\\\\D=96\\\\b)32=\frac{192}{\sqrt{m}}\\\\  32*\sqrt{m}=192\\\\\sqrt{m}=\frac{192}{32}=6\\\\m=36

8 0
3 years ago
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
Read 2 more answers
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