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3 years ago

Evaluate the expression. ║4/13║

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

7 0

Answer:

4/13

Step-by-step explanation:

In absolute value, it is showing distance. Whenever something is in absolute value, it is turned positive.

here, Inside the absolute value brackets, we have positive 4/13. Positive 4/13 undergoes no such change, because there are no other terms, and no negatives.

absolute value of 4/13 is 4/13

anastassius [24]3 years ago

6 0

Answer:

$\frac{4}{13}$

Step-by-step explanation:

those lines around the equation mean that the answer is always positive, this is called absolute value

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aev [14]

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Step-by-step explanation:

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3 years ago

Suppose a city with population 300 comma 000 has been growing at a rate of 3% per year. If this rate continues, find the popul

viktelen [127]

Answer:

The population of this city in 13 years is 440,550.

Step-by-step explanation:

Given:

Suppose a city with population 300, 000 has been growing at a rate of 3% per year.

Now, to find the population of this city in 13 years.

Let the population of this city in 13 years be $A.$

Population ( $P$ ) = 300,000.

Rate per year ( $r$ ) = 3%.

Time ( $t$ ) = 13 years.

Now, we put formula to get the population of the city in 13 years:

$A=P(1+r)^t\\\\A=300,000(1+3\%)^{13}\\\\A=300,000(1+0.03)^{13}\\\\A=300,000(1.03)^{13}\\\\A=300,000\times 1.4685\\\\A=440,550.$

Therefore, the population of this city in 13 years is 440,550.

3 0

3 years ago

Use induction to prove that 2? ?? for any integer n>0 . Indicate type of induction used.

Hoochie [10]

Answer with explanation:

The given statement is which we have to prove by the principal of Mathematical Induction

$2^{n}>n$

1.→For, n=1

L H S =2

R H S=1

2>1

L H S> R H S

So,the Statement is true for , n=1.

2.⇒Let the statement is true for, n=k.

$2^{k}>k$

---------------------------------------(1)

3⇒Now, we will prove that the mathematical statement is true for, n=k+1.

$\rightarrow 2^{k+1}>k+1\\\\L H S=\rightarrow 2^{k+1}=2^{k}\times 2\\\\\text{Using 1}\\\\2^{k}>k\\\\\text{Multiplying both sides by 2}\\\\2^{k+1}>2k\\\\As, 2 k=k+k,\text{Which will be always greater than }k+1.\\\\\rightarrow 2 k>k+1\\\\\rightarrow2^{k+1}>k+1$