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Sergeeva-Olga [200]
3 years ago
7

Determine whether each given expression is equivalent to 6 x 4 1/2 or is not equivalent by checking the appeopriate box in the t

able below
А 6 x 4 + 2
B 6x5-1/2
C 6x4+6x1/2
D 6 x 5-6x1/2

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
7 0
I think it’s B. 6 x 4 + 2
Simora [160]3 years ago
6 0
It would be the answer B??
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Use the multiplier method to increase £72 by 12%<br> You must show your working.
cricket20 [7]

Answer:

£80.62

Step-by-step explanation:

100+12%=112%

112/100= 1.12

1.12*£72 =£80.62

5 0
3 years ago
In triangle ABC, AD is a median. FE is a straight line parallel to BC cutting the remaining sides AB at F and AC at E and cuttin
daser333 [38]

Answer:

Step-by-step explanation:

since AD is a median it implies that triangle ABC is bisected to two equal right angled triangle which are ADB and ADC.

FE is parrallel to BC and cuts AB at F and AC at E shows that there are two similar triangles formed which are AFE and ABC.

Recall that ADC is a right angled triangle, ED bisects a right angled triangle the the ADE = 45^{o}.

Now, Let FD bisect angle ADB,

  then ADF = 45^{o} too.

Since AFX is similar to Triangle ABD and that Triangle AEX is similar to Triangle ACD, then EDX is similar to FDX

FDE = ADF + ADE = 90^{o}

4 0
4 years ago
Please help, WILL GIVE BRAINLIST
Arada [10]

Answer:

I would say B

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Calculate the sum of the first 30 terms in the sequence that begins with 70,65,60
Afina-wow [57]

\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\ddddddddddddddddddd \displaystyle \Large \boldsymbol{} a_1=70  \  ; \ d=-5  \\\\S_n=\frac{a_1+a_n}{2} \cdot n \ ; \ a_n=a_1+(n-1)d \Longrightarrow \\\\\\ S_{30}=\frac{70+70-29\cdot5}{2} \cdot 30 =-75 \\\\\\Answer: S_{30}=-75

4 0
3 years ago
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
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