A submarine sits at -300 meters in relation to sea level. Then it descends 115 meters. What is it’s new position in relation to
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<h3><u>Solution</u></h3>
<u>Given </u><u>:</u><u>-</u>
- Perimeter of rectangle = 72 cm
- The length is 3 more than twice the width.
<u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u>
- Dimensions of rectangle
<u>Using </u><u>Formula</u>
<u>Let,</u>
- Length of Rectangle = x cm
- Breadth of Rectangle = y cm
<u>According</u><u> to</u><u> question</u><u>,</u>
==> perimeter of Rectangle = 72
==> 2(x+y) = 72
==> x + y = 72/2
==> x + y = 36_________________(1)
<u>Again,</u>
==> x = 2y + 3
==> x - 2y = 3__________________(2)
<u>Subtract</u><u> </u><u>equ(</u><u>1</u><u>)</u><u> </u><u>&</u><u> </u><u>equ(</u><u>2</u><u>)</u>
==> y + 2y = 36 - 3
==> 3y = 33
==> y = 33/3
==> y = 11
<u>keep </u><u>in </u><u>equ(</u><u>1</u><u>)</u>
==> x - 2×11 = 3
==> x = 3 + 22
==> x = 25
<h3><u>Hence</u></h3>- <u>Length</u><u> of</u><u> </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u> </u><u>cm</u>
- <u>Width </u><u>of </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u> </u><u>cm</u>