Answer:

Explanation:
Hello there!
In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

Then, we plug in the variables to obtain:

Regards!
The answer is D, species!
Hope this helps!
Answer:
Metal name (charge in roman numerals) Non metal
for example Iron (III) chloride
Explanation:
The rule for naming special transition metal are as follows -
a) First name the transition metal
b) Now write the name of the non metal in the chemical formula.
c) Write the charge for the non metal.
d) If there is a polyatomic ion, write the Common Ion Table ,its formula and charge.
e) Based on the total charge on the non-metal or polyatomic ion, deduce the total charge on the transition metal
f) Write the charge of transition metal after the name of metal in Roman Numeral in parentheses
<h3>
![\tt C.~Ka=\dfrac{[H^+][CN^-]}{[HCN]}](https://tex.z-dn.net/?f=%5Ctt%20C.~Ka%3D%5Cdfrac%7B%5BH%5E%2B%5D%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D)
</h3><h3>Further explanation </h3>
According to Arrhenius, acids are substances which, when dissolved in water, release Hions.
An HₓY acid in water will ionize:
HₓY (aq) ⇒ xH⁺ (aq) + Yˣ- (aq)
In general, the weak acid ionization reaction
HA (aq) ⇒ H⁺ (aq) + A⁻ (aq)
Ka's value
![\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKa%20%5C%3A%20%3D%20%5C%3A%20%5Cfrac%20%7B%5BH%20%5E%20%2B%5D%20%5BA%20%5E%20-%5D%7D%20%7B%5BHA%5D%7D%7D%7D%7D)
So for HCN
HCN(aq)⇒H⁺(aq)+CN⁻(aq)
![\tt Ka=\dfrac{[H^+][CN^-]}{[HCN]}](https://tex.z-dn.net/?f=%5Ctt%20Ka%3D%5Cdfrac%7B%5BH%5E%2B%5D%5BCN%5E-%5D%7D%7B%5BHCN%5D%7D)
Answer: Isotopes
Explanation:
The atoms of a chemical element can exist in different types. These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses.
Hope this helps!