2. How are these nutrients used by your body?

1 answer:

7 0

The nutrients that the body breaks down into basic units are carbohydrates, fats, and proteins. From carbohydrates comes glucose, your body's -- especially the brain's -- primary form of fuel; from fats we get glycerol and fatty acids, many of which are essential ingredients in hormones and the protective sheath in our brain that covers communicating neurons; and from proteins we get amino acids, which are the building blocks to lots of structures, including our blood, muscle, skin, organs, antibodies, hair, and fingernails.

Each of these nutrients travels down a different pathway, but all can eventually fuel the body's production of ATP (adenosine triphosphate), which is essentially our bodies' ultimate energy currency.

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6.5 moles AlCl3 reacts with 57.0g of NaOH. how many grams of Al(OH)3 will be produced

Alona [7]

The equation for the reaction between NaOH and AlCl₃ is as follows;
3NaOH + AlCl₃ ---> 3NaCl + Al(OH)₃
the stoichiometry of NaOH : AlCl₃ is 3:1
3 moles of NaOH reacts with 1 mol of AlCl₃ to produce 1 mol of Al(OH)₃
the number of AlCl₃ moles reacted - 6.5 mol
molar mass of NaOH -(23 +16 +1) = 40 g/mol
the number of NaOH moles reacted = 57.0 g / 40 g/mol
NaOH moles = 1.425 mol
either NaOH or AlCl₃ is in excess and other is the limiting reactant.
limiting reactant is the reactant whose number of moles are fully consumed during the reaction. the reactant that is in excess will have leftover moles that are remaining after the reaction.
If AlCl₃ is the limiting reactant, number of NaOH moles would be thrice the amount of AlCl₃ present,
then number of NaOH moles that should be present - 6.5 * 3 = 19.5 mol
however there are only 1.425 mol of NaOH present, therefore AlCl₃ is in excess.
Then NaOH is the limiting reactant,
the amount of products formed depends on the amount of the limiting reactant present.
stoichiometry of NaOH : Al(OH)₃ is 3:1
the number of Al(OH)₃ moles produced = number of NaOH moles reacted / 3
number of Al(OH)₃ moles are - 1.425 mol /3 = 0.475 mol
molar mass of Al(OH)₃ = (27 +3*16 + 3*1) = 78 g/mol
mass of Al(OH)₃ produced = 78 g/mol * 0.475 mol = 37.05 g

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3 years ago

Place the items in order from highest to lowest degree of internal organization.

zimovet [89]

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3 years ago

Read 2 more answers

What is the molarity of a solution of 0.2 moles of Potassium Oxide

egoroff_w [7]

The molarity of a solution : 0.4 M

<h3>Further explanation</h3>

Given

0.2 moles of Potassium Oxide

500 ml of water = 0.5 L

Required

The molarity

Solution

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Assume volume of solution = volume of water(addition of solution volume from volume Potassium Oxide is negligible

Input the value :

M = 0.2 : 0.5

M = 0.4

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3 years ago

Possible isomers of C4H9I

amm1812

Answer:

there are 4 possible isomers

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3 years ago

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3(s)→CaO(s)+CO2(

Mazyrski [523]

Answer is: <span>mass of calcium carbonate needed is 120 grams.
</span>Chemical reaction: CaCO₃(s) → CaO(s) + CO₂(g)<span>.
</span>V(CO₂) = 27.0 L.
Vm = 22.4 L/mol.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 27 L ÷ 22.4 L/mol.
n(CO₂) = 1.2 mol.
From chemical reaction: n(CO₂) : n(CaCO₃) = 1 : 1.
m(CaCO₃) = 1.2 mol.
m(CaCO₃) = n(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 1.2 mol · 100 g/mol.
m(CaCO₃) = 120 g.

3 0

4 years ago