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4 years ago

2. How are these nutrients used by your body?

1 answer:

7 0

The nutrients that the body breaks down into basic units are carbohydrates, fats, and proteins. From carbohydrates comes glucose, your body's -- especially the brain's -- primary form of fuel; from fats we get glycerol and fatty acids, many of which are essential ingredients in hormones and the protective sheath in our brain that covers communicating neurons; and from proteins we get amino acids, which are the building blocks to lots of structures, including our blood, muscle, skin, organs, antibodies, hair, and fingernails.

Each of these nutrients travels down a different pathway, but all can eventually fuel the body's production of ATP (adenosine triphosphate), which is essentially our bodies' ultimate energy currency.

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Why does Tom Zambrano think that renewable energy science is a good choice for a career?

ella [17]

Answer:

There will many opportunities in the field of renewable energy science and engineering. It is an exciting field, with a lot of variety and room for new ideas.

Explanation:

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3 years ago

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How many atoms of hydrogen are in 4Ca(OH)2

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Explanation:

there are 8 atoms of hydrogen

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2 years ago

Use the given data at 500 K to calculate ΔG°for the reaction

Anton [14]

Answer : The value of $\Delta G^o$ for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

$2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)$

First we have to calculate the enthalpy of reaction $(\Delta H^o)$ .

$\Delta H^o=H_f_{product}-H_f_{reactant}$

$\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]$

where,

$\Delta H^o$ = enthalpy of reaction = ?

n = number of moles

$\Delta H_f^0$ = standard enthalpy of formation

Now put all the given values in this expression, we get:

$\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]$

$\Delta H^o=-1035.6kJ=-1035600J$

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction $(\Delta S^o)$ .

$\Delta S^o=S_f_{product}-S_f_{reactant}$

$\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]$

where,

$\Delta S^o$ = entropy of reaction = ?

n = number of moles

$\Delta S_f^0$ = standard entropy of formation

Now put all the given values in this expression, we get:

$\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]$

$\Delta S^o=-153J/K$

Now we have to calculate the Gibbs free energy of reaction $(\Delta G^o)$ .

As we know that,

$\Delta G^o=\Delta H^o-T\Delta S^o$

At room temperature, the temperature is 500 K.

$\Delta G^o=(-1035600J)-(500K\times -153J/K)$

$\Delta G^o=-959100J=-959.1kJ$

Therefore, the value of $\Delta G^o$ for the reaction is -959.1 kJ

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3 years ago

The graphics below shows how photosynthesis and cellular respiration are related.

lisov135 [29]

Options found from another source are:

a. oxygen. b. glucose. c. energy stored as ATP. d. carbon dioxide and water

Answer:

c energy stored as ATP

Explanation:

Cellular respiration converts glucose into energy in the form of ATP (c). The answer cannot be oxygen (a), because this is required for this process as a final electron acceptor. In terms of photosynthesis, oxygen is released as a by-product. The answer cannot be glucose (b) because that is our starting point for respiration, and what is synthesised during photosynthesis. The answer cannot be (d) as carbon dioxide and water are released by cellular respiration, and required by photosynthesis

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4 years ago

The following properties are either physical or chemical. Which one is different from the rest based on those two categories? (5

Yuliya22 [10]

Answer:

The following properties are either physical or chemical. Which one is different from the rest based on those two categories? We chose all of the above

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3 years ago