<u>Answer:</u>
<u>For a:</u> The concentration of
ions in the solution are 6 M and 2 M respectively.
<u>For b:</u> The concentration of
ions in the solution are 0.5 M and 1.0 M respectively.
<u>For c:</u> The concentration of
ions in the solution are 0.051 M and 0.051 M respectively.
<u>For d:</u> The concentration of
ions in the solution are 1.34 M and 0.67 M respectively.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
......(1)
Or,
...(2)
For the given options:
The chemical formula of sodium phosphate is 
Moles of sodium phosphate = 0.0200 moles
Volume of solution = 10.0 mL
Putting values in equation 1, we get:

1 mole of sodium phosphate produces 3 moles of
ions and 1 mole of
ions
So, concentration of 
Concentration of 
Hence, the concentration of
ions in the solution are 6 M and 2 M respectively.
The chemical formula of barium nitrate is 
Moles of barium nitrate = 0.300 moles
Volume of solution = 600.0 mL
Putting values in equation 1, we get:

1 mole of barium nitrate produces 1 mole of
ions and 2 mole of
ions
So, concentration of 
Concentration of 
Hence, the concentration of
ions in the solution are 0.5 M and 1.0 M respectively.
The chemical formula of potassium chloride is KCl
Given mass of potassium chloride = 1.00 g
Molar mass of potassium chloride = 39 g/mol
Volume of solution = 0.500 L
Putting values in equation 1, we get:

1 mole of potassium chloride produces 1 mole of
ions and 1 mole of
ions
So, concentration of 
Concentration of 
Hence, the concentration of
ions in the solution are 0.051 M and 0.051 M respectively.
The chemical formula of ammonium sulfate is 
Given mass of ammonium sulfate = 132 g
Molar mass of ammonium sulfate = 132 g/mol
Volume of solution = 1.50 L
Putting values in equation 1, we get:

1 mole of ammonium sulfate produces 2 moles of
ions and 1 mole of
ions
So, concentration of 
Concentration of 
Hence, the concentration of
ions in the solution are 1.34 M and 0.67 M respectively.