Answer:
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<span>The molar heat of solution of NaOH is -445,100 J/mol. To compute much heat (in J) will be released if 40.00 g of NaOH are dissolved in water, we first convert the given grams of NaOH to moles of NaOH, and use the given molar heat of solution to compute for the energy. (Using dimensional analysis):
40 g NaOH x (1 mol NaOH/ 40 g NaOH) x (-445100 J / 1 mol NaOH) = -445100 J of energy.</span>
Answer:
TRUE!!!!
Explanation:
Water can act as both an acid and a base in solution and undergoes autoionization, where it can be both an acid and a base to itself. When mixed with an acid, water accepts hydrogen ions and acts as a base. However, when water is mixed with a base, it donates hydrogen ions and acts like an acid.
Not my words! I hope this helps :)
Answer:
V₂ = 317 L
Explanation:
Given data:
Initial number of moles of hydrogen = 18.9 mol
Initial volume of gas = 428 L
Final volume = ?
Final number of moles = 14.0 mol
Solution:
According to the Avogadro law,
Number of moles of gas is directly proportional to the volume of gas at constant temperature and pressure.
Mathematical expression:
V₁/n₁ = V₂/n₂
V₁ = Initial Volume of balloon
n₁ = initial number of moles
V₂ = Final volume of balloon
n₂ = Final number of moles
Now we will put the values.
428 L / 18.9 mol = V₂/ 14 mol
V₂ =428 L × 14 mol / 18.9 mol
V₂ = 5992 L /18.9
V₂ = 317 L
Answer:
5.3%
Explanation:
Let the volume be 1 L
volume , V = 1 L
use:
number of mol,
n = Molarity * Volume
= 0.8846*1
= 0.8846 mol
Molar mass of CH3COOH,
MM = 2*MM(C) + 4*MM(H) + 2*MM(O)
= 2*12.01 + 4*1.008 + 2*16.0
= 60.052 g/mol
use:
mass of CH3COOH,
m = number of mol * molar mass
= 0.8846 mol * 60.05 g/mol
= 53.12 g
volume of solution = 1 L = 1000 mL
density of solution = 1.00 g/mL
Use:
mass of solution = density * volume
= 1.00 g/mL * 1000 mL
= 1000 g
Now use:
mass % of acetic acid = mass of acetic acid * 100 / mass of solution
= 53.12 * 100 / 1000
= 5.312 %
≅ 5.3%
