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xxTIMURxx [149]
3 years ago
12

How long does a bullet take to travel 12.7cm when going 360 m/s

Physics
2 answers:
Vinil7 [7]3 years ago
8 0

Answer: 3.53 x 10^-4 s

Explanation:

12.7cm x 1m/100cm = 0.127m

V = d/t

t x V = d

t = d/v = 0.127m/(360m/s) = 0.000353s or 3.53 x 10^-4

Helen [10]3 years ago
7 0

Answer:

0.000352 seconds

Explanation:

Speed = \frac{Distance}{Time} or \\Time = \frac{Distance}{Speed}  = \frac{\frac{12.7}{100}} {360}

Time = 0.000352 seconds

Given Distance in centimetres is converted to metres

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In terms of diameter, the planet Saturn is larger than _______ , but smaller than _______.
hram777 [196]

ANSWER:

NEPTUNE & JUPITER

5 0
3 years ago
Answer these questions plz​
lozanna [386]

1. The property of a conductor by virtue of which it posses the flow of electric current through it is called resistance.

2. The resistance of a conductor depends on the cross sectional area of the conductor and it's resistivity.

3.This id due to the fact that the resistance of a wire is inversely proportional to the square of its diameter.

4.Due to at high temperatures , the alloy donot oxidize. Alloy doesn't melt readily and get deformed.

8 0
3 years ago
A +71 nC charge is positioned 1.9 m from a +42 nC charge. What is the magnitude of the electric field at the midpoint of these c
viva [34]

Answer:

The net Electric field at the mid point is 289.19 N/C

Given:

Q = + 71 nC = 71\times 10^{- 9} C

Q' = + 42 nC = 42\times 10^{- 9} C

Separation distance, d = 1.9 m

Solution:

To find the magnitude of electric field at the mid point,

Electric field at the mid-point due to charge Q is given by:

\vec{E} = \frac{Q}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}

\vec{E} = \frac{71\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}

\vec{E} = 708.03 N/C

Now,

Electric field at the mid-point due to charge Q' is given by:

\vec{E'} = \frac{Q'}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}

\vec{E'} = \frac{42\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}

\vec{E'} = 418.84 N/C

Now,

The net Electric field is given by:

\vec{E_{net}} = \vec{E} - \vec{E'}

\vec{E_{net}} = 708.03 - 418.84 = 289.19 N/C

5 0
3 years ago
PLEASE HELP! **
Eduardwww [97]
It moves to 56 km per hours
8 0
4 years ago
One of the factors that determines the ? of a capacitor is the frequency measured in hertz.
ycow [4]

Answer:

Reactance

Explanation:

In an AC circuit, the capacitive reactance of a capacitor is given by:

X_C = \frac{1}{2 \pi f C}

where

f is the frequency of the AC current

C is the capacitance of the capacitor

The reactance of the capacitor tells somehow the "resistance" of the capacitor to the passage of current through it. In fact:

- When the frequency of the AC current is zero (this means, we are in regime of DC current), the reactance becomes infinite, and this is true because the capacitor does not let the current pass through it)

- When the frequency of the AC current tends to infinite, the reactance becomes zero, and this is true because in this case the current changes direction so fast that the capacitor has not enough time to "block" the current, so the current almost no feels the presence of the capacitor.

7 0
4 years ago
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