I need help with all of these questions

A transverse wave is set up in a very long string. The oscillator is set at 20.0 Hz, and the wave speed is 78 m/s. The amplitude

Sedbober [7]

To solve this problem we must apply the concepts related to Tangential Acceleration based on angular velocity and acceleration, and therefore, we must also calculate angular velocity based on the given frequency. For all these problems we will take the Units to the International System. The maximum acceleration would then be defined as,

$a_{max} = \omega^2 A$

Here,

$\omega$ = Angular velocity

A = Amplitude

At the same time the angular velocity is described as,

$\omega = 2\pi f$

Here f means the frequency of the wave. Substituting,

$\omega = 2 \pi (20)$

$\omega = 40\pi$

$A = 5.2cm$

$A = 0.052m$

Replacing at the first equation,

$a_{max} = (40\pi )^2 (0.052)$

$a_{max} = 821.15m/s^2$

Therefore the maximum particle acceleration for a point on the string is $821.15m/s^2$

6 0

3 years ago

A 65-kg bungee jumper, who is attached to one end of an 85-m long bungee cord that has its other end tied to a bridge, jumps off

irinina [24]

Answer:

The impulse delivered to the bungee jumper is 1.32 kN.s

Explanation:

The situation can be shown graphically as shown in the figure.

Impulse delivered to the bungee jumper = Area under the curve.

The curve represents a triangle and the area of traiangle = (1/2)base×height

The base of the triangle from the graph = 1.2 seconds.

The height of the triangle from the graph = 2.2 kN

Thus,

<u>Impulse = (1/2)×(1.2 seconds)×(2.2 kN) = 1.32 kN.s</u>

3 0

3 years ago

A student using a tuning fork of frequency 512 Hz observes that the speed of sound is 340.0 m/s. What is the wavelength of this

Romashka [77]

Answer:

0.066m

Explanation:

Step one:

given

frequency =512 Hz

The speed of sound is 340.0 m/s.

Required

The wavelength

Step two:

the formula for wavelength is

$v=f \lambda$

$\lambda= v/f$

substitute the given data

$\lambda= 340/514\\\\\lambda= 0.66m$

5 0

3 years ago

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 3.37 times a second. A tack is stuck in the tire a

zhannawk [14.2K]

Answer:

The tangential speed of the tack is 8.19 m/s.

Explanation:

The wheel rotates 3.37 times a second that means wheel complete 3.37 revolutions in a second. Therefore, the angular speed ω of the wheel is given as follows:

$\omega =3.37rev/s \times(\frac{2\pi rad}{1s} )\\\\=21.174rad/s$

Use the relation of angular speed with tangential speed to find the tangential speed of the tack.

The tangential speed v of the tack is given by following expression

v = ω r

Here, r is the distance to the tack from axis of rotation.

Substitute 21.174 rad/s for ω, and 0.387 m for r in the above equation to solve for v.

v = 21.174 × 0.387

v = 8.19m/s

Thus, The tangential speed of the tack is 8.19 m/s.

4 0

3 years ago

Read 2 more answers

A player kicks a ball across the grass. what causes the ball to slow down to stop

vlada-n [284]

Answer: Friction

Explanation: Friction caused m by the ball rubbing against the grass and ground cause it to lose energy in the form of thermal energy and slow down

7 0

4 years ago