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Crank
3 years ago
6

Convection currents will transfer heat throughout a gas until what condition arises

Physics
2 answers:
Ivenika [448]3 years ago
6 0
The answer is D.
_______
maria [59]3 years ago
4 0

Answer:

D) The gas has the same temperature throughout

Explanation:

In case of heat transfer due to convection we will say that thermal energy is transferred by the movement of the molecules itself.

Here we know that in convection mode of heat transfer the molecules which are at high temperature will rise above due to lesser density.

Due to this density difference all the molecules of gas at high temperature moves upwards and heavy particles of gas at low temperature comes down.

In this way the molecules will move along with thermal energy and the energy is transferred by convection method.

But if all the gas molecules comes to same temperature then the heat can not flow as there is no density difference and hence there is no energy transfer through the medium

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The mass of 2 cm3 of gold is 38.6 grams. find the density of the gold. Could you please help me??
Alex Ar [27]

Density = mass/ volume (so here this is how you would solve the problem)

<span>D = 38.6 g/ 2 cm3 (first step)</span>

<span>D= 19.3 g/cm3  ( Do math and then you would get this)</span>

<span>
</span>

<span>Hope this helps!! :) </span>


6 0
3 years ago
A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction
andrew11 [14]

Answer:

Explanation:

Velocity at the bottom of height h

= √2gh

deceleration on rough horizontal surface

= μg , μ is coefficient of friction

= .27 x 9.8

= 2.646 m / s²

v² = u² - 2as

0 = 2gh - 2 x 2.646 x 19

h =  2 x 2.646 x 19  / 2 x 9.8

= 5.13 m  

8 0
3 years ago
A flywheel with radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.400 rad/s2.For a po
oksian1 [2.3K]

Answer:

0.12\ m/s^2

Explanation:

Given that,

The radius of a flywheel, r = 0.3 m

Angular acceleration of a flywheel, \alpha =0.4\ rad/s^2

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The relation between the tangential and angular acceleration is given by :

a_t=r\alpha \\\\a_t=0.3\times 0.4\\\\a_t=0.12\ m/s^2

So, the required magnitude of tangential acceleration is 0.12\ m/s^2.

6 0
3 years ago
A ball thrown into the air has its greatest kinetic energy as it reaches the highest point in its path. please select the best a
postnew [5]
F - False.

Its greatest kinetic energy is at the point of release.

It has the least kinetic energy, zero, at its highest point in its path.
3 0
3 years ago
Read 2 more answers
Aspect of the physical world
Zepler [3.9K]

Answer:

Not enough information given. Are there answer choices? Or more details given in the question?

Explanation:

6 0
3 years ago
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