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loris [4]
3 years ago
12

The higher an electromagnetic wave's frequency, the lower its

Physics
2 answers:
Pepsi [2]3 years ago
7 0

Answer:

The higher an electromagnetic wave's frequency, the lower its wavelength

~batmans wife dun dun dun...

tensa zangetsu [6.8K]3 years ago
3 0

Answer:

The higher an electromagnetic wave's frequency, the lower its wavelength.

Explanation:

The frequency of a electromagnetic wave is given by the following relation :

c=f\times \lambda

Where

c = speed of light

f = frequency of a wave

\lambda = wavelength

f=\dfrac{c}{\lambda}

It is clear that the frequency of a wave has inverse relationship with its wavelength. So, higher the electromagnetic wave's frequency, the lower its wavelength.

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A tetrahedron has an equilateral triangle base with 25.0-cm-long edges and three equilateral triangle sides. The base is paralle
djverab [1.8K]

Answer:

a. 7.046 Nm²/C

b. 2.348 Nm²/C

Explanation:

Data given:

Base of equilateral triangle = 25.0 cm = 0.25 m

Strength of electric field = 260 N/C

In order to find the electric flux we first have to find out the area of triangle.

Area of triangle = \frac{\sqrt{3} }{4} a^{2}

                         = \frac{\sqrt{3} }{4} (0.25)^{2}

                         = 0.0271 m³

Lets find electric flux,

      Electric Flux = E. A

                          = 260×0.0271

                          = 7.046 Nm²/C

Now we can find the electric flux through each of the three sides.

Electric flux through three sides = \frac{7.046}{3}

                                                = 2.348 N m²/C

       

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