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3 years ago

Which types of basketball injuries do you believe the warm-up could prevent? Explain

Physics

1 answer:

inn [45]3 years ago

7 0

Answer:

pulling a muscle. putting too much strain on a muscle causing a tear.

Explanation:

Doing warm ups help your muscles adjust to the full extent of a basketball game. Warming up is like stretching, helps your muscles adjust before going full out on the court.

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The two concepts or issues that you chose and explain how each either has contributed to or detracted from social change, specif

Rom4ik [11]

Racial equality directed to a scenario in which individuals of all races and ethnicities exists treated equally, regardless of any differences in physical characteristics.

<h3>What is meant by racial equality? </h3>

Racial equality occurs when organizations, like schools, give people of all races equal chances regardless of their physical characteristics, such skin color. It has always been difficult for ethnic minorities to achieve equality, especially in educational institutions.

According to research, black pupils face fewer expectations from their teachers and are more likely to be suspended or expelled than white students. They are also less likely to be enrolled in gifted programs.

The term "racial equality" describes a situation in which people of all races and ethnicities are treated equally, regardless of any physical distinctions. Racial equality occurs when institutions uphold people's moral, legal, and political rights.

To learn more about Racial equality refer to:

brainly.com/question/12645755

#SPJ9

3 0

1 year ago

A ball bounced by a basketball player on the floor bounces back up at her. Newton's First Law Newton's Second Law Newton's Third

taurus [48]

Answer:

Newton's Third Law of Motion

Explanation:

Newton's Third Law of Motion which states that, for every action there is an equal but opposite reaction.

This ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects.

In this scenario, a ball bounced by a basketball player on the floor bounces back up at her.

According to Newton's Third Law of Motion, the statement above simply means that in every interaction, there is a pair of forces acting on the two interacting objects i.e the ball and floor. The size of the force on the ball equals the size of the force on the floor. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

Hence, the ball bounced by the basketball player on the floor would bounce back in equal magnitude.

4 0

2 years ago

A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has radius 11.0 cm ,

viktelen [127]

Part A)
First of all, let's convert the radii of the inner and the outer sphere:
$r_A = 11.0 cm = 0.110 m$
$r_B = 16.5 cm=0.165 m$
The capacitance of a spherical capacitor which consist of two shells with radius rA and rB is
$C=4 \pi \epsilon _0 \frac{r_A r_B}{r_B- r_A}=4\pi(8.85 \cdot 10^{-12}C^2m^{-2}N^{-1}) \frac{(0.110m)(0.165m)}{0.165m-0.110m}=$
$=3.67\cdot 10^{-11}F$

Then, from the usual relationship between capacitance and voltage, we can find the charge Q on each sphere of the capacitor:
$Q=CV=(3.67\cdot 10^{-11}F)(100 V)=3.67\cdot 10^{-9}C$

Now, we can find the electric field at any point r located between the two spheres, by using Gauss theorem:
$E\cdot (4 \pi r^2) = \frac{Q}{\epsilon _0}$
from which
$E(r) = \frac{Q}{4 \pi \epsilon_0 r^2}$
In part A of the problem, we want to find the electric field at r=11.1 cm=0.111 m. Substituting this number into the previous formula, we get
$E(0.111m)=2680 N/C$

And so, the energy density at r=0.111 m is
$U= \frac{1}{2} \epsilon _0 E^2 = \frac{1}{2} (8.85\cdot 10^{-12}C^2m^{-2}N^{-1})(2680 N/C)^2=3.17 \cdot 10^{-5}J/m^3$

Part B) The solution of this part is the same as part A), since we already know the charge of the capacitor: $Q=3.67 \cdot 10^{-9}C$ . We just need to calculate the electric field E at a different value of r: r=16.4 cm=0.164 m, so
$E(0.164 m)= \frac{Q}{4 \pi \epsilon_0 r^2}=1228 N/C$

And therefore, the energy density at this distance from the center is
$U= \frac{1}{2}\epsilon_0 E^2 = \frac{1}{2} (8.85\cdot 10^{-12}C^2m^{-2}N^{-1})(1228 N/C)^2=6.68 \cdot 10^{-6}J/m^3$

8 0

3 years ago

If the light wave has a wavelength of 10m what would be its velocity

s2008m [1.1K]

If this case could ever happen, the speed would follow from this formula:

$v = f \cdot \lambda$

with f the frequency and lambda the wavelength. We are give a wavelength of 10m. The frequencies of the visible light can range between 400 to about 790 Terahertz, so let us pick a middle point of 600 THz ("green-ish") as a "representative."

$v = 600THz\cdot 10m = 6\cdot 10^{14} \frac{1}{s}\cdot 10 m = 6\cdot10^{15}\frac{m}{s}$

The speed of such a wave would have to be 6e+15 m/s (which would be 7 orders of magnitude higher than the universal speed of light constant)

7 0

3 years ago

Read 2 more answers

PLEASE ANSWER THIS WILL MARK AS BRAINLIEST PLEASE USE TRUTHFUL ANSWERS PLEASE

luda_lava [24]

Australia separated from other continents and species there evolved independently

8 0

2 years ago