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hichkok12 [17]
3 years ago
11

A uniform disk, a uniform hoop, and a uniform solid sphere are released at the same time at the top of an inclined ramp. They al

l roll without slipping. In what order do they reach the bottom of the ramp

Physics
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

sphere, disk, hoop

Explanation:

See attached file

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Why do soundwaves move faster than the ground than through the air​
Sati [7]

Answer:

Particles of matter are packed more tightly in the ground than in the air

Explanation:

the reason is that sound waves are vibrations of the molecules of the medium: therefore, if the particles of the medium are closer together (as in solids), the vibrations can be transmitted faster, and the wave can travel faster

8 0
4 years ago
What types of cuts do jig saw sanders make?​
LuckyWell [14K]
The jigsaw can be used to make both straight and curved cuts in a wide variety of materials, including wood, particleboard, plywood, plastic, metal, even ceramic tile. There is also way more than those, but those are just the basics or common things. Hope this helps!
7 0
3 years ago
Read 2 more answers
A single frictionless roller-coaster car of mass m = 55 kg tops the first hill with speed v0 at height h = 22.0 m. How much work
sertanlavr [38]

The gravitational potential energy of the roller-coaster at point A and B respectively 11870.10 Joule and 5935.05 Joule.

<h3 /><h3>What is gravitational potential energy?</h3>

The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.

According to the question:

Mass of the rollercoaster: m = 55 kg.

Height of point A: h =22.0 m.

Height of point B: h/2 = 22.0/2 m = 11.0 m.

Height of point C = 0.

Taking, acceleration due to gravity: g = 9.81 m/s² we get:

The gravitational potential energy of the car at point A:

E₁ = mgh = 55 kg × 9.81 m/s² × 22.0 m = 11870.10 Joule.

The gravitational potential energy of the car at point B:

E₂ = mgh/2 = 55 kg × 9.81 m/s² × 11.0 m = 5935.05 Joule.

Hence, gravitational potential energy of the car at point A and B respectively 11870.10 Joule and 5935.05 Joule.

Learn more about gravitational potential energy here:

brainly.com/question/19768887

#SPJ1

6 0
1 year ago
At night a land breeze forms because
NemiM [27]

The wind will blow from the higher pressure over the water to lower pressure over the land causing the sea breeze. The sea breeze strength will vary depending on the temperature difference between the land and the ocean. At night, the roles reverse. The air over the ocean is now warmer than the air over the land.

not giving you the answer but hopefully this gives a hint

3 0
4 years ago
The work function for potassium is 2.24 eV. If potassium metal is illuminated with light of wavelength 350 nm , find:
7nadin3 [17]
Photo electric effect.Some guidance notes which may help ...
The energy of a photon of wavelength lambda is E=hc/lambda where h is Plank's constant, c is the speed of light, and lambda is the wavelength.The units of eV (electron volts) and the value of Planck's constant probably have to be determined. Calculate E=hc/lambda as hx3x10^8/(350x10^-9) and compare that to 2.24eV (expressed in consistent units which could be Joules)If the 350nm photon energy is higher than 2.24eV, then the difference should be the kinetic energy of the ejected photo electron.
if a photon has equal to or less than 2.24 eV work function, then it won't be ejected. That wavelength can be found by equating the work function to the photon energy using the equation E=hc/lambda2.24eV=hx3x10^8/(lambda_cut_off)

If the incoming light photon has an energy less than the work function of the metal, then the metal will not emit a photon.
This is the photo-electric effect, explained by Einstein who got a Nobel prize for this, and also for relativity. The point was, it seems, that it didn't matter how intense the light source was, it was the energy of photons within the light source, expressed by their wavelength, that mattered. 
If you want any further information please ask.
8 0
3 years ago
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