Answer:
The motorbike is traveling at 40 m/s
Explanation:
100m over 2.5 seconds or 100/2.5 is 40 m/s
Explanation:
It is given that,
Diameter of loops, d = 48 cm = 0.48 m
Radius of the loop, r = 0.24 m
Current carried in the loop, I = 4.5 A
Distance between loops, x = 30 cm = 0.3 m
Speed of the proton, v = 2600 m/s
We know that the magnetic field at the midway of the coils is given by :
Let F is the magnetic force these loops exert on the proton just after it is fired. It is given by :
So, the magnetic force these loops exert on the proton is . Hence, this is the required solution.
Answer:
Lets take
u =velocity
θ =angle from horizontal
The horizontal component of velocity = u cosθ
The vertical component of velocity = u sinθ
The horizontal distance x in time t
x = u cosθ .t -----------1
The vertical distance y in time t
--------2
t= x/(u cosθ) ( tanθ=sinθ/cosθ)
Form above we can say that path of the projectile motion is parabolic.
What's the rest of this and it prob family or group