A "derived unit" is a specific combination of base units with its own name. <em>(3)</em>
Examples:
<u>Combination of base units</u> <u>Its own name</u>
kilogram-meter / second² Newton
Coulomb / second Ampere
kilogram-meter² / second² (Newton-meter) Joule
kilogram-meter² / second³ (Joule / sec) Watt
Answer: B, Radiation
Explanation: idk just got that out from Mr.Google
Answer:
the energy comes from the increase in the electric field
Explanation:
The capacitance is
C = ε₀ A / d
The electric charge on the condenser plates
Q = C ΔV
The stored electrical energy is
U = ½ C ΔV²
ΔV = E d
U = ½ (ε₀ A / d) (E d)²
U = ½ ε₀ A d E²
We see that the stored energy is proportional to the square of the electric field, so the capacitor can increase its energy with increasing voltage
In short, the energy comes from the increase in the electric field
To solve this problem it is necessary to apply the concepts related to Hooke's Law as well as Newton's second law.
By definition we know that Newton's second law is defined as
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
m = mass
a = Acceleration
By Hooke's law force is described as
![F = k\Delta x](https://tex.z-dn.net/?f=F%20%3D%20k%5CDelta%20x)
Here,
k = Gravitational constant
x = Displacement
To develop this problem it is necessary to consider the two cases that give us concerning the elongation of the body.
The force to keep in balance must be preserved, so the force by the weight stipulated in Newton's second law and the force by Hooke's elongation are equal, so
![k\Delta x = mg](https://tex.z-dn.net/?f=k%5CDelta%20x%20%3D%20mg)
So for state 1 we have that with 0.2kg there is an elongation of 9.5cm
![k (9.5-l)=0.2*g](https://tex.z-dn.net/?f=k%20%289.5-l%29%3D0.2%2Ag)
![k (9.5-l)=0.2*9.8](https://tex.z-dn.net/?f=k%20%289.5-l%29%3D0.2%2A9.8)
For state 2 we have that with 1Kg there is an elongation of 12cm
![k (12-l)= 1*g](https://tex.z-dn.net/?f=k%20%2812-l%29%3D%201%2Ag)
![k (12-l)= 1*9.8](https://tex.z-dn.net/?f=k%20%2812-l%29%3D%201%2A9.8)
We have two equations with two unknowns therefore solving for both,
![k = 3.136N/cm](https://tex.z-dn.net/?f=k%20%3D%203.136N%2Fcm)
![l = 8.877cm](https://tex.z-dn.net/?f=l%20%3D%208.877cm)
In this way converting the units,
![k = 3.136N/cm(\frac{100cm}{1m})](https://tex.z-dn.net/?f=k%20%3D%203.136N%2Fcm%28%5Cfrac%7B100cm%7D%7B1m%7D%29)
![k = 313.6N/m](https://tex.z-dn.net/?f=k%20%3D%20313.6N%2Fm)
Therefore the spring constant is 313.6N/m