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Scorpion4ik [409]
4 years ago
7

6a. A special lamp can produce UV radiation. Which two statements

Physics
1 answer:
alexandr1967 [171]4 years ago
4 0

Answer:

The correct options are:

B) They have the same wave speed as visible light

D) They have a lower frequency than gamma rays.

Explanation:

B) Ultraviolet rays, commonly known as UV rays, are a type of electromagnetic ways. As electromagnetic waves, in the layman's term, are all kinds of life that can be identified, all electromagnetic waves (UV rays, visible light, infrared, radio etc) all travel with the same velocity, that is the speed of light, given as v = 3 × 10⁸ m/s

D) The frequency of all electromagnetic rays can be found by electromagnetic spectrum (picture attached below).

We can clearly see in the picture that the frequencies of UV rays lie at about 10¹⁵ - 10¹⁶ Hz which is lower than the frequency of Gamma ray, which lie at about 10²⁰ Hz.

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You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using e
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You are working for a manufacturing company, which is mathematically given as

  • m=3\sqrt{2}
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<h3>What is the value of m that will place the movable bead in equilibrium at x-a a ....?</h3>

a)

Generally, the equation for the force of equilibrium is mathematically given as

F=2fcos\theta

Therefore

K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3

m=3\sqrt{2}

b)

By force equilibrium

K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}

Therefore

n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\

m=\frac{15\sqrt{5}}{16}

c)

K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}

x^2+a^2=(14/3)^{2/3}x^2

x=a/1.338

x=0.747a

d)

By force equilibrium

K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}

m/n=\frac{(x^2+a^2)3/2}{x^3}

Read more about electric fields

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