When the wire is twice as long. Also when the cross sectional area is halved
Answer:
if it is slowing down than it is gaining potential energy
Explanation:
Explanation:
An IC engines means an Internal Combustion engine. Here, the combustion takes place in side a chamber or a cylinder internally, hence it is known as internal combustion engine.
Combustion is the process where oxygen reacts with the fuel and it burns to produce a large amount of force and heat. In each revolution of the crank, the engine creates a power stroke when the piston goes from the bottom dead center to the top dead center.
During each power stroke, the energy released forces the piston down and the crankshaft is rotated.
Answer:
It's actually 100V
Explanation:
To answer this, you'd need to use Ohm's law, which states that Voltage is equivalent to the product of Current and Resistance (V=IR).
V = 50 × 2
V = 100
Therefore the voltage is a 100V.
None of the answers you have listed match this though, so I'm guessing it either must be typo or the question itself is wrong.
Well, I'll try to write the formula in a way that's not confusing,
but I'm afraid it might be slightly confusing anyway.
When you're working with dB, the basic rule is
A change of 10 dB means either multiplying or dividing by 10 .
Multiply something by 10 ==> it increases by 10 dB.
Divide something by 10 ==> it decreases by 10 dB.
It turns out that another way to write all of this is . . .
An increase of 10 dB ===> multiply the original amount by 10¹
An increase of 20 dB ===> multiply the original amount by 10²
An increase of, say, 7 dB ===> multiply the original amount by 10⁰·⁷
A decrease of 10 dB ===> multiply the original amount by 10⁻¹
A decrease of 30 dB ===> multiply the original amount by 10⁻³
A decrease of, say, 13 dB ===> multiply the original amount by 10⁻¹·³
This question says: The sound increases by 5 dB .
That means the original 'intensity' or 'power' of the sound
is multiplied by
10⁰·⁵ = √10 = about 3.162 (rounded) .
From the choices listed, the closest one is (c).
