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Nastasia [14]
3 years ago
6

Ejercicio 5. En el año 1985 fue puesto en órbita el primer satélite de México, el Morelos 1. Dicho satélite orbitaba la Tierra a

una altura de 35 800 km (35.8 x10^6 m).
a) Obtenga el radio de la órbita del satélite (r = R +h)
b) Calcule la velocidad del Morelos 1
c) Obtenga el periodo de rotación en horas
d) ¿Cuál es el valor de la intensidad del campo gravitacional en la órbita del Morelos 1?
Physics
1 answer:
Charra [1.4K]3 years ago
3 0

Answer:

a) Obtenga el radio de la órbita del satélite (r = R +h)

Explanation:

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According to Kepler's Third Law, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about
NARA [144]

Answer:

Orbital period, T = 1.00074 years

Explanation:

It is given that,

Orbital radius of a solar system planet, r=4\ AU=1.496\times 10^{11}\ m

The orbital period of the planet can be calculated using third law of Kepler's. It is as follows :

T^2=\dfrac{4\pi^2}{GM}r^3

M is the mass of the sun

T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times (1.496\times 10^{11})^3    

T^2=\sqrt{9.96\times 10^{14}}\ s

T = 31559467.6761 s

T = 1.00074 years

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6 0
3 years ago
Which value is equivalent to 7.2 kilograms? A. 720 grams B. 7,200 grams C. 72,000 grams D. 720 milligrams E. 7,200 milligrams
Aneli [31]
1 kilogram = 1,000 grams
1 kilogram = 1,000,000 milligrams
8 0
3 years ago
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A space probe is directly between two moons of a planet. If it is twice as far from moon A as it is from moon B, but the net for
Dennis_Churaev [7]

Answer:

c. Moon A is four times as massive as moon B

Explanation:

Let's assume the:

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  • mass of the moon B = M_B\,kilogram
  • distance between the center of masses of the object and moon B = r\,meters

According to the given condition the object is twice as far from moon A as it is from moon B

  • ∴distance between the center of masses of the object and moon B = 2r\,meters

<u>As we know, gravitational force of attraction is given by:</u>

F=G\frac{m_1.m_2}{r^2}

<em>According to the condition</em>

Force on m due toM_B=Force on m due toM_A

G\frac{m.M_A}{(2r)^2} =G\frac{m.M_B}{(r)^2}

\frac{M_A}{4r^2} =\frac{M_B}{r^2}

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3 0
3 years ago
If you precisely measure the position of a particle, you
pochemuha
<h2>Answer: destroy all information about its speed or momentum</h2>

The Heisenberg uncertainty principle postulates that the fact that <u>each particle has a wave associated with it</u>, imposes restrictions on the ability to determine its <u>position</u> and <u>speed</u> at the same time.  

In other words:  

<h2>It is impossible to measure <u>simultaneously </u>(according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.  </h2>

So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity.  

It should be noted that this uncertainty does not derive from the measurement instruments, but from the measurement itself. Because, even with the most precise devices, the uncertainty in the measurement continues to exist.  

Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.  

3 0
3 years ago
A bus makes a 10-kilometer journey through town. It's top speed is 50 km/h and it's mean speed is 16kn/h. Explain why these spee
Maru [420]

Answer:

speed are different at different places

Explanation:

because it's top speed is 50km/h,so it's initial speed may be less. when it covers some distance it's speed changes again. then we have given a mean speed .mean speed means sum of all speed divided by sum of total time.so the mean speed and final speed differs from each other

6 0
3 years ago
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