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seraphim [82]
3 years ago
10

Emma a total of 25 seconds to crawl 4 feet south and then 6 feet east.

Physics
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

what is the question exactly

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I). Mechanical energy is the sum of potential energy and kinetic energy in an object that is used to do work.
Dmitry_Shevchenko [17]

Answer:

false statement : b )  For the motion of a cart on an incline plane having a coefficient of kinetic friction of 0.5, the magnitude of the change in kinetic energy equals the magnitude of the change in gravitational potential energy

Explanation:

mechanical energy = potential energy + kinetic energy = constant

differentiating both side

Δ potential energy + Δ kinetic energy = 0

Δ potential energy = -  Δ kinetic energy

first statement is true.

Friction is a non conservative force so inter-conversion of potential and kinetic energy is not possible in that case. In case of second  option,  the correct relation is as follows

change in gravitational potential energy = change in kinetic energy + work done against friction .

So given 2 nd  option is incorrect.

In case of no change in gravitational energy , work done is equal to

change in kinetic energy.

4 0
3 years ago
What would happen if you drop and egg
dexar [7]

Answer:

It would crack.

Explanation: The pressure from dropping it would crush the eggshell therefore breaking the egg.

5 0
3 years ago
Read 2 more answers
A spinning coil of wire is what moves the cone in a speaker, producing the sound. True/False
Georgia [21]

False, the spinning coil of wire that moves the cone in a speaker does not produces sound.

<u>Explanation</u>:

The wire coil is an electromagnet that is fixed to speaker cone. A normal magnet attached to the back of the speaker cone.When audio is sent in the form of short bursts of electric current to the speaker cone through the wire.

A magnetic field is induced when electric current allowed to pass through the coil. This magnetic field is repelled by the other magnet. This repulsion cause the cone to move forward. In the absence of  electric current in the coil, the cone moves backward.

Thus sound waves are produced due to the resulting rarefaction and compression.  So it is not the spinning coil of wire but he permanent magnet that produces the sound.

5 0
4 years ago
Read 2 more answers
A 100kg crate slides along a floor with a starting velocity of 21ms If the force due to friction is 8N how long will it take for
GaryK [48]

A 100kg crate slides along a floor with a starting velocity of 21 m/s. If the force due to friction is 8N, then, it will take 262.5 s for the box to come to rest.

We'll begin by calculating the declaration of the box. This can be obtained as follow:

Force (F) = –8 N (opposition)

Mass (m) = 100 Kg

<h3>Deceleration (a) =? </h3>

<h3>F = ma</h3>

–8 = 100 × a

Divide both side by 1000

a = \frac{-8}{100}

<h3>a = –0.08 ms¯²</h3>

Therefore, the deceleration of the box is –0.08 ms¯²

Finally, we shall determine the time taken for the box to come to rest. This can be obtained as follow:

Deceleration (a) = –0.08 ms¯²

Initial velocity (u) = 21 ms¯¹

Final velocity (v) = 0 ms¯¹

<h3>Time (t) =.? </h3>

<h3>v = u + at</h3>

0 = 21 + (–0.08×t)

0 = 21 – 0.08t

Collect like terms

0 – 21 = –0.08t

–21 = –0.08t

Divide both side by –0.08

t = \frac{-21}{-0.08}\\\\

<h3>t = 262.5 s</h3>

Therefore, it will take 262.5 s for the box to come to rest.

Learn more: brainly.com/question/14446351

7 0
2 years ago
As capacitor was discharging, what did you observe about q on its plates and the motion of charges in the external circuit?
liubo4ka [24]

As capacitor was discharging, The charge on the plate got reversed and the motion of charge is opposite to the flow of current.

The charging contemporary asymptotically processes 0 as the capacitor becomes charged up to the battery voltage.

The capacitor is completely charged when the voltage of the electricity supply is equal to that at the capacitor terminals. that is referred to as capacitor charging; and the charging segment is over when modern-day stops flowing thru the electrical circuit.

A capacitor can be slowly charged to the important voltage and then discharged quick to provide the power wanted. it's far even viable to charge several capacitors to a positive voltage and then discharge them in any such way as to get extra voltage out of the gadget than became installed.

Learn more about capacitor here:-brainly.com/question/14883923

#SPJ4

8 0
2 years ago
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