All categories

4 years ago

Which option best defines parallel lines?

1 answer:

7 0

Parallel lines are coplanar lines (lines that lie on the same plane) and they do not intersect.

It’s important to understand that they remain the same distance apart over their entire lengthy which means they never get closer together of farther away from each other.

You might be interested in

Helppppppppppp pllleeasseee

Leno4ka [110]

The answer is C because the formula for a right triangle is a^2 +b^2=c^2

4 0

3 years ago

Read 2 more answers

0/35-31/35-2/35= Reduce if possible

sineoko [7]

Hi!

I will write it like this to make it easier to see:

$\frac{0}{35} - \frac{31}{35} - \frac{2}{35}$

Seeing this, we can right away take the $\frac{0}{35}$ away to make it easier, because 0/35 is 0. Now, we are left with:

$-\frac{31}{35} - \frac{2}{35}$

Since the denominators (the 35s) are the same, we do not have to mess with those. We simply subtract the numerators (-31 - 2) and we get -33. Therefore, your answer is :

$-\frac{33}{35}$

Hope this helps! Have a great day! :D

4 0

2 years ago

There is an unknown number •it is a four digit number •the tens are double the ones •the thousands are double the tens •the sum

oksano4ka [1.4K]

Answer:

8542

Statement

1.It is a four digit number

2.The tens are double the ones

3.The thousands are double the tens

4.The sum of the digits is nineteen

Step-by-step explanation:

It is a four digit number

lets take 4 digit number-ABCD

The tens are double the ones

$C=2D$ -----------------------------1

The thousands are double the tens

$A=2C$ -------------------------------2

According to equation 1 and 2

$A=4D$

If we take

$D=1,2$

Possible number

$4B21$ OR $8B42$

The sum of the digits is nineteen

I use hit and trial method

$4B21$ - If I take B is maximum

$4+9+2+1\neq 19$

$8B42$ - If, i try to find value of B

$8+B+4+2=19$ ---------------------3

$14+B=19\\B=19-14\\B=5$

So the unknown number is- 8542

6 0

4 years ago

What do changes in a graphs slopes on a distance-versus-time graph mean?

AleksAgata [21]

Answer:quadratic formula

simple method

3 0

3 years ago

Read 2 more answers

Show that an integer is divisible by 11 if and only if the alternating sum (add first digit, subtract the second, add the third,

Bess [88]

Answer and Step-by-step explanation:

Suppose that we have a number y which is a positive integer and that:

y = $x_n...x_5x_4x_3x_2x_1x_0$

Where;

$x_{0}$ = digit at 10⁰ => one's place (units place)

$x_1$ = digit at 10¹ => 10's place (tens place)

$x_{2}$ = digit at 10² => 100's place (hundreds place)

$x_{3}$ = digit at 10³ => 1000's place (thousands place)

$x_{n}$ = digit at 10ⁿ place

Then;

y = $x_{0}$ * 10⁰ + $x_1$ * 10¹ + $x_{2}$ * 10² + $x_{3}$ * 10³ + $x_{4}$ * 10⁴ + $x_5$ * 10⁵ + . . . + $x_{n}$ * 10ⁿ

Since 10⁰ = 1, let's rewrite y as follows;

y = $x_{0}$ + $x_1$ * 10¹ + $x_{2}$ * 10² + $x_{3}$ * 10³ + $x_{4}$ * 10⁴ + $x_5$ * 10⁵ + . . . + $x_{n}$ * 10ⁿ

Now, to test if y is divisible by 11, replace 10 in the equation above by -1. Since 10 divided by 11 gives -1 (mod 11) [mod means modulus]

y = $x_{0}$ + $x_1$ * (-1)¹ + $x_{2}$ * (-1)² + $x_{3}$ * (-1)³ + $x_{4}$ * (-1)⁴ + $x_5$ * (-1)⁵ + . . . + $x_{n}$ * (-1)ⁿ

=> y = $x_{0}$ - $x_1$ + $x_{2}$ - $x_{3}$ + $x_{4}$ - $x_5$ + . . . + $x_{n}$ (-1)ⁿ (mod 11)

Therefore, it can be seen that, y is divisible by 11 if and only if alternating sum of its digits $x_{0}$ - $x_1$ + $x_{2}$ - $x_{3}$ + $x_{4}$ - $x_5$ + . . . + $x_{n}$ (-1)ⁿ is divisible by 11

Let's take an example

Check if the following is divisible by 11.

i. 1859

Solution

1859 is divisible by 11 if and only if the alternating sum of its digit is divisible by 11. i.e if (1 - 8 + 5 - 9) is divisible by 11.

1 - 8 + 5 - 9 = -11.

Since -11 is divisible by 11 so is 1859

ii. 31415

Solution

31415 is divisible by 11 if and only if the alternating sum of its digit is divisible by 11. i.e if (3 - 1 + 4 - 1 + 5) is divisible by 11.

3 - 1 + 4 - 1 + 5 = 10.

Since 10 is not divisible by 11 so is 31415 not divisible.

3 0

4 years ago